Answer:
Area of the shades region = 244.6 ft²
Step-by-step explanation:
Area of the shaded region = Area of the rectangle ABCD- Area of the right angle triangle DEC
Area of the rectangle = Length × width
= 29.8 × 13
= 387.4 ft²
By applying Pythagoras theorem in the right triangle DEC,
(Hypotenuse)² = (leg 1)² + (leg 2)²
CD² = DE² + EC²
(29.8)² = DE² + (28)²
888.04 = DE² + 784
DE² = 888.04 - 784
DE = 10.2 ft
Area of ΔDEC = 
= 
= 142.8 ft²
Area of the shades region = 387.4 - 142.8
= 244.6 ft²
Answer: a
Step-by-step explanation:
Answer:
3
Step-by-step explanation:
Given: Sphere A and Sphere B are similar.
The volumes of A and B are 17
and 136
The diameter of B is 6 cm.
To find: diameter of A
Solution:
Let R denotes radius of sphere A and r denotes radius of sphere B.
Radius of sphere A= R
Diameter of sphere B = 6 cm
So, radius of sphere B (r) = 
Volume of sphere is 
Volume of sphere A = 

Put r = 3 cm

Diameter of sphere A = 2 × Diameter
= 2 × 1.5
=3 cm
Given problems:
Line parallel that passes through (2,3);
Solution:
To solve this problem, we need to first understand what parallel lines are.
A parallel line is any two line that does not meet at any point.
In order to achieve this, both lines must have the same slope.
So, we find the slope of the given line and write in the form for a straight line.
Slope of line = 
let x₁, y₁ = (-2, -1)
x₂, y₂ = (2 , -3)
Now input the parameters and solve for the slope;
Slope of line =
=
Any line that would be parallel to this must have the same slope.
Equation of a straight line;
y = mx + c;
y and x are the coordinates;
m is the slope
c is the y-axis intercept;
From (2, 3);
y = 3 and x = 2; m =
3 =
x 2 + C
3 =
+ C
C = 
So the equation of the line is;
y =
+
Multiply through by 3;
3y = -2x + 13
The equation of the line is 3y = -2x + 13