Answer:
x < −4
Step-by-step explanation:
−3x + 5 > 17
Subtract 5 from both sides.
−3x > 17 − 5
Subtract 5 from 17 to get 12.
−3x > 12
Divide both sides by −3. Since −3 is < 0, the inequality direction is changed.
Divide 12 by −3 to get −4.
So then you get x < −4 which is your answer.
I’m not sure if it’s right
Answer:
b=4.9
C. is the correct option.
Step-by-step explanation:
In triangle TGN,
Let <RTG be x
cosx= b/h
or, cosx = 2/a
Again,
In triangle TRG,
cosx = b/h
(for bigger right angled triangle)
cosx = a/(4+2)
cosx = a/6
Now
cosx = 2/a = a/6
or, 2/a = a/6
or, 12 = a²
so, a² = 12
Now,
For TRG,
h² = p²+b²
or, 6² = b² + a²(a²=12)
or, 6² = b² + 12
or, 36 = b² + 12
or, 36 -12 = b²
or, b² = 24
or, b = square root 24
so, b = 4.8989
so, b = 4.9
To answer this question, you need to know that a quarter is worth $0.25 and dimes worth $0.10. In this case, the total number of money that made from quarters and dimes is $2.80
With Q=quarter and D=dime, then the equation should be:
2.80= 0.25 Q + 0.10 D
The condition that needs to be fulfilled in this case is that the quarter should be 8 more than dimes. Then you need to find out the highest possible number of the quarter and lowest possible number of the dimes.
If you divide 2.8 with 0.25 you will found it will be 11.2 but 11 quarter will result with 0.05 value which you cannot remove, so the highest possible of the quarter should be 10.
If the highest possible of the quarter is 10, then the lowest possible of dimes should be:
2.8= 0.25(10) + 0.10D
0.10D= 0.3
D=3
Since 10-3 is 7, then it is not possible for the quarter to be 8 more than the dimes.
Answer:
D: x < 20
Step-by-step explanation:
-4x + 16 > -64
subtract 16 from both sides because you must isolate x.
-4x + 16 - 16 > -64 - 16
-4x > -80
Then divide -4 on both sides... I believe that when you divide a number by a negative number you must flip the sign...
-4x/ -4 < -80/ -4
x < 20
(negative divided by a negative will result in a POSITIVE.)
Hope this helped... I truly apologize if this is wrong..
