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sergejj [24]
3 years ago
10

Which of these is equivalent to the law of conservation of energy?

Physics
1 answer:
zalisa [80]3 years ago
7 0
The answer is D.
C and A are incomplete as they only treat specific types of energy, and B doesn't answer the question.
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B. In the vicinity of Earth’s orbit around the Sun, the energy intensity of sunlight is about 1600 W/m2 . What is the approximat
Vera_Pavlovna [14]

Answer:

1097.8 V/m

Explanation:

The equation that relates the intensity of an electromagnetic wave with the magnitude of the electric field is:

I=\frac{1}{2}c\epsilon_0 E^2

where

c is the speed of light

\epsilon_0 is the vacuum permittivity

E is the peak magnitude of the electric field

In this problem, we know the intensity:

I = 1600 W/m^2

So we can rearrange the formula to find E:

E=\sqrt{\frac{2I}{c\epsilon_0}}=\sqrt{\frac{2(1600 W/m^2)}{(3\cdot 10^8 m/s)(8.85\cdot 10^{-12} F/m)}}=1097.8 V/m

4 0
3 years ago
PLZZZZZZZZZZ HELP QUICK!!!!!!!!!!!!
kifflom [539]
In an atom of hydrogen the orbit radius is given by the formula:
r = n² · α₀

where:
n = number of orbit = 15
α₀ = Bohr radius (innermost radius) = 0.529 Â

Since d = 2 · r, we can write:
d = n² · d₀
   = 15² · 1.06
   =  238.5 Â

Hence, the <span>diameter of the fifteenth orbit of the hydrogen atom is 238.5 </span>Â.
8 0
3 years ago
Which is a common unit of density?<br><br> A. The g<br> B. G/ml<br> C. Cm3<br> D. G/s
Anika [276]
The correct answer is B.g/mL
6 0
4 years ago
If the organ pipe is cut in half, what is the new fundamental frequency? if the organ pipe is cut in half, what is the new funda
bogdanovich [222]

The frequency for a fundamental pipe is given as:

f = v/4L

L is equal to the length of the pipe

Since L = Lo/2 where Lo is the original length of the pipe, the new frequency would be:

f = (v/4)/(Lo/2)

f = 2 (v/4Lo)

Since v/4Lo = fo, therefore:

f = 2 fo

8 0
4 years ago
According to Coulomb's law, if the separation between two particles of the same charge increases four times, the potential energ
Lera25 [3.4K]

Answer:

c.   V = k Q1 * Q2 / R1      potential energy of Q1 and Q2 separated by R

V2 / V1 = (R1 / R2) = 1/4

V2 = V1 / 4

8 0
3 years ago
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