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4 years ago

5

Organizational charts are used to identify statistical data. Please select the best answer from the choices provided. True or fa

lse?

2 answers:

Law Incorporation [45]4 years ago

8 0

False, I just did it.

natita [175]4 years ago

7 0

<span>False.
Organizational charts are the</span> graphic representation of the structure of an organization which shows the relationships of the positions within it.

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Tragedy deals with light, trivial subjects. True False

Arte-miy333 [17]

Answer:

False

Step-by-step explanation:

Tragedy deals with great suffering, destruction and distress.

two definitions of tragedy:

-an event causing great suffering, destruction, and distress, such as a serious accident, crime, or natural catastrophe.

-a play dealing with tragic events and having an unhappy ending, especially one concerning the downfall of the main character.

4 0

3 years ago

For a school play, Rico bought 3 adult tickets and 5 child tickets for $40. Sasha bought 1 adult ticket and 5 child tickets for

Serhud [2]

The cost of one adult ticket is $7.5 and one child ticket is $3.5

Julia will pay $48 for 5 adult tickets and 3 child tickets.

Step-by-step explanation:

Let,

Cost of one adult ticket = x

Cost of one child ticket = y

According to given statement;

3x+5y=40 Eqn 1

x+5y=25 Eqn 2

Subtracting Eqn 2 from Eqn 1

$(3x+5y)-(x+5y)=40-25\\3x+5y-x-5y=15\\2x=15$

Dividing both sides by 2

$\frac{2x}{2}=\frac{15}{2}\\x=7.5$

Putting x=2.5 in Eqn 1

$3(7.5)+5y=40\\22.5+5y=40\\5y=40-22.5\\5y=17.5$

Dividing both sides by 5

$\frac{5y}{5}=\frac{17.5}{5}\\y=3.5$

The cost of one adult ticket is $7.5 and one child ticket is $3.5

5 adult tickets = 5*7.5 = $37.5

3 child tickets = 3*3.5 = $10.5

Total = 37.5+10.5 =$48

Julia will pay $48 for 5 adult tickets and 3 child tickets.

Keywords: linear equation, subtraction

Learn more about subtraction at:

#LearnwithBrainly

8 0

3 years ago

<img src="https://tex.z-dn.net/?f=f%28x%29%20%3D%20%5Cfrac%7Bx-5%7D%7B2x%5E%7B2%7D-5x-3%20%7D" id="TexFormula1" title="f(x) = \f

Vedmedyk [2.9K]

i) The given function is

$f(x)=\frac{x-5}{2x^2-5x-3}$

The factored form is

$f(x)=\frac{x-5}{(x-3)(2x+1)}$

The domain are the values of x for which the function is defined.

$(x-3)(2x+1)\ne 0$

$(x-3)\ne0,(2x+1)\ne 0$

$x\ne3,x\ne-\frac{1}{2}$

ii) To find the vertical asymptotes, equate the denominator to zero.

$(x-3)(2x+1)=0$

$(x-3)=\ne0,(2x+1)=0$

$x=3,x=-\frac{1}{2}$

iii) To find the roots, equate the numerator to zero.

$x-5=0$

The root is $x=5$

iv) To find the y-intercept, put $x=0$ into the function.

$f(0)=\frac{0-5}{(0-3)(2(0)+1)}$

$f(0)=\frac{-5}{(-3)(1)}$

$f(0)=\frac{5}{3}$

The y-intercept is $\frac{5}{3}$

v) The horizontal asymptote is given by;

$lim_{x\to \infty}\frac{x-5}{2x^2-5x-3}=0$

The horizontal asymptote is $y=0$

vi) The function is not reducible. There are no holes.

vii) The given function is a proper rational function.

Proper rational functions do not have oblique asymptotes.

3 0

3 years ago

Read 2 more answers

To arrive at its destination on time the bus should have maintained a speed of vv kilometers per hour throughout the journey. In

yulyashka [42]

Answer:

The answer to the question is

The actual duration of the trip is 8/9 times the normal duration or the bus arrived 1/9 times earlier than it would have at a constant speed of v kph

Step-by-step explanation:

Speed of bus in the first third distance = v kph

Speed of bus for the remaining two thirds = 1.2 v kph

To solve the question, we note that speed = distance/time

therefore time = distance/speed

Let the distance of the destination be D, then

Normal duration at speed v = D/v

Actual duration (D/3)÷v + (2D/3)÷(1.2v) ⇒ (1.2*D/3 + 2D/3)1.2v

= $\frac{D}{3v} +\frac{5D}{9v}$ = (8/9)×D/v

Therefore the actual duration is 8/9 times the normal duration

7 0

4 years ago

The radius r(t) of the base of a cone is increasing at a rate of 10 meters per second. The height h(t) of the cone is fixed at 6

IceJOKER [234]

Answer:

dV/dt = 40π

Step-by-step explanation:

We are told that The radius r(t) of the base of a cone is increasing at a rate of 10 meters per second. Thus;

dr/dt = 10 m

Height: h = 6 m

Volume of cone is given by the formula;

V = ⅓πr²h

dV/dr = ⅔πrh

We want to find the rate at which the volume is changing at radius of 1m.

Thus;

dV/dt = (dV/dr) × (dr/dt)

dV/dt = ⅔π(1 × 6) × (10)

dV/dt = 40π

8 0

3 years ago