Answer:
probability that the other side is colored black if the upper side of the chosen card is colored red = 1/3
Step-by-step explanation:
First of all;
Let B1 be the event that the card with two red sides is selected
Let B2 be the event that the
card with two black sides is selected
Let B3 be the event that the card with one red side and one black side is
selected
Let A be the event that the upper side of the selected card (when put down on the ground)
is red.
Now, from the question;
P(B3) = ⅓
P(A|B3) = ½
P(B1) = ⅓
P(A|B1) = 1
P(B2) = ⅓
P(A|B2)) = 0
(P(B3) = ⅓
P(A|B3) = ½
Now, we want to find the probability that the other side is colored black if the upper side of the chosen card is colored red. This probability is; P(B3|A). Thus, from the Bayes’ formula, it follows that;
P(B3|A) = [P(B3)•P(A|B3)]/[(P(B1)•P(A|B1)) + (P(B2)•P(A|B2)) + (P(B3)•P(A|B3))]
Thus;
P(B3|A) = [⅓×½]/[(⅓×1) + (⅓•0) + (⅓×½)]
P(B3|A) = (1/6)/(⅓ + 0 + 1/6)
P(B3|A) = (1/6)/(1/2)
P(B3|A) = 1/3
Answer:64
Step-by-step explanation:
67
Answer:
The quadratic curve has the best correlation to the given data.
Step-by-step explanation:
Enter the data into a spreadsheet or graphing calculator and try the different regression options to see which gives the highest R-value. Here, the quadratic regression does that.
Tetrahedron has 4 faces so it's a pyramid, dodecahedron is 12 faces, octahedron is 8 faces, icosahedron has 20 faces. Easiest way I know to classify them
Well we can find the perimeter by using the formula P=2L + 2W
P=2(30) + 2(18) P=60+36 P=96
I believe we can divide the perimeter by 18 to find the total amount of lights needed.
96÷18=5.333333
So we know at least 5 lights are needed.
I'm not sure if I'm correct, but I hope this helped anyways :)
