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2 years ago

HEY CAN ANYONE PLS ANSWER MY MATH QUESTION!!!!1

Mathematics

2 answers:

Alenkinab [10]2 years ago

7 0

Answer:

The blue and yellow macaw is 33 inches long.

Step-by-step explanation:

If the toucan is 22 inches long and it's two thirds the length of the macaw you can divide by two to find what one third is.

22 ÷ 2 = 11

So then you have to multiply by 3 to find what the full length is.

3 x 11 = 33 inches

Hope that helps and have a great day!

Alex2 years ago

4 0

Answer:

33 in

Step-by-step explanation:

Let the length of the macaw be x
The length of the toucan is 22 in

Then we have equation

x*2/3 = 22
x = 22 ÷ 2/3
x = 22*3/2
x = 33 in

Blue-and-yellow macaw is 33 in long

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A train is exactly 24km from Smalltown at 7:00p.m. It travels toward Smalltown at a constant rate of 90km per hour. At what time

N76 [4]

Answer:

7:16 P.M.

Step-by-step explanation:

24/90=4/15. There are 60 minutes in an hour, so we have 240/15=16.

5 0

3 years ago

PLEASE HELP. FUNCTIONS AND RELATIONS. PROVIDE ANSWER OPTION A,B,C OR D? THANKS!!

baherus [9]

Step-by-step explanation:

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6 0

1 year ago

2 Here are two equations:

MatroZZZ [7]

a. (3,4) is only the solution to Equation 1.

(4, 2.5) is the solution to both equations

(5,5) is the solution to Equation 2

(3,2) is not the solution to any equation.

b. No, it is not possible to have more than one (x,y) pair that is solution to both equations

Step-by-step explanation:

a. Decide whether each neither of the equations,

i (3,4)

ii. (4,2.5)

ill. (5,5)

iv. (3,2)

To decide whether each point is solution to equations or not we will put the point in the equations

Equations are:

Equation 1: 6x + 4y = 34

Equation 2: 5x – 2y = 15

i (3,4)

Putting in Equation 1:

$6(3) + 4(4) = 34\\18+16=34\\34=34\\$

Putting in Equation 2:

$5(3) - 2(4) = 15\\15-8 = 15\\7\neq 15$

ii. (4,2.5)

Putting in Equation 1:

$6(4) + 4(2.5) = 34\\24+10=34\\34=34\\$

Putting in Equation 2:

$5(4) - 2(2.5) = 15\\20-5 = 15\\15=15$

ill. (5,5)

$6(5) + 4(5) = 34\\30+20=34\\50\neq 34$

Putting in Equation 2:

$5(5) - 2(5) = 15\\25-10 = 15\\15=15$

iv. (3,2)

$6(3) + 4(2) = 34\\18+8=34\\26\neq 34$

Putting in Equation 2:

$5(3) - 2(2) = 15\\15-4 = 15\\11\neq 15$

Hence,

(3,4) is only the solution to Equation 1.

(4, 2.5) is the solution to both equations

(5,5) is the solution to Equation 2

(3,2) is not the solution to any equation.

b. Is it possible to have more than one (x, y) pair that is a solution to both

equations?

The simultaneous linear equations' solution is the point on which the lines intersect. Two lines can intersect only on one point. So a linear system cannot have more than one point as a solution

So,

a. (3,4) is only the solution to Equation 1.

(4, 2.5) is the solution to both equations

(5,5) is the solution to Equation 2

(3,2) is not the solution to any equation.

b. No, it is not possible to have more than one (x,y) pair that is solution to both equations

Keywords: Linear equations, Ordered pairs

Learn more about linear equations at:

#LearnwithBrainly

8 0

2 years ago

Solve 2cos ²y -siny -1=0 for 0° ≤y≤360°

natima [27]

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5 0

2 years ago

Solve for x: 2|x − 3| + 1 = 7 (5 points) x = 0, x = 6 x = −1, x = 6 x = 0, x = 9 No solutions

Dominik [7]

2|x-3|+1=7
2|x-3|=6
|x-3|=3

x-3 = 3 or x-3 = -3
x=0 or 6

8 0

2 years ago

Read 2 more answers