Answer:
Let p(x) = x3 + ax2 + bx +6
(x-2) is a factor of the polynomial x3 + ax2 + b x +6
p(2) = 0
p(2) = 23 + a.22 + b.2 +6 =8+4a+2b+6 =14+ 4a+ 2b = 0
7 +2 a +b = 0
b = - 7 -2a -(i)
x3 + ax2 + bx +6 when divided by (x-3) leaves remainder 3.
p(3) = 3
p(3) = 33 + a.32 + b.3 +6= 27+9a +3b +6 =33+9a+3b = 3
11+3a +b =1 => 3a+b =-10 => b= -10-3a -(ii)
Equating the value of b from (ii) and (i) , we have
(- 7 -2a) = (-10 - 3a)
a = -3
Substituting a = -3 in (i), we get
b = - 7 -2(-3) = -7 + 6 = -1
Thus the values of a and b are -3 and -1 respectively.
Step-by-step explanation:
Y=-6-x is not equal to 2x+y=12. Both sides were not divided by two when it was simplified.
Answer:
(2 x +1) ( x + 1) = 2 x² + 3 x + 1
Step-by-step explanation:
The steops used to find the product of (2 x + 1) (x + 1) are
=( 2 x )× x + (2 x) × 1 + x + 1
= 2 x² + 2 x + x + 1
= 2 x² + 3 x + 1
Answer:
7:1
Step-by-step explanation:
28:4=
7(4):1(4)=
7:1
Hope this helps!
Answer:
Image result for State the domain and range in set notation
The domain is the set of all first elements of ordered pairs (x-coordinates). The range is the set of all second elements of ordered pairs (y-coordinates). Only the elements "used" by the relation or function constitute the range. Domain: all x-values that are to be used (independent values).
Step-by-step explanation:
