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3 years ago

Find the perimeter and area

Mathematics

2 answers:

irinina [24]3 years ago

8 0

Perimeter = All side lengths added together

P = 8+8+5+5

Perimeter = 26

Area for Quadrilateral = (base)(height)

A = (8)(5)

Area = 40

Nitella [24]3 years ago

5 0

Answer:

Step-by-step explanation: Perimeter is distance around the outside so 8+8+5+5=26 units

Area - I'll get back with you

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Add 4 kg 250 g, 2 kg 90 g and 19kg 3 g.

GarryVolchara [31]

Answer:

=25343 grams or 25 kg 343 g.

Step-by-step explanation:

1 kg = 1000 g

∴ 4 kg = 4000 grams

and the 4 kg 250 g would equal = 4250 grams.

∴ 2 kg = 1000 g

2 kg 90 g = 2000 grams + 90 g = 2090 grams

∴ 19 kg = 19000 grams

and 19 kg 3 grams = 19000 grams + 3 grams = 19003 grams

now we will add all of the values together to get the final answer.

4250 grams + 2090 grams + 19003 grams = 25343 grams or 25 kg 343 g.

Hope this helps!!

8 0

3 years ago

What is the angular size of Mars, as seen from the Earth, when it was closest to the Earth?

lesantik [10]

The angular size of Mars, as seen from the Earth, when it was closest to the Earth is 25 arcseconds.

<h3>What is angular size?</h3>

It should be noted that angular size is the object's apparent size as seen from an observer on Earth.

At its closest approach, the angular size of Mars is 25 arcseconds. This was known through the use of a telescope.

Learn more about Mars on:

brainly.com/question/644043

#SPJ1

5 0

2 years ago

Evaluate the integral ∫2−1|x−1|dx

defon

I think you might be referring to the definite integral,

$\displaystyle \int_{-1}^2|x-1|\,\mathrm dx$

Recall the definition of absolute value:

$|x| = \begin{cases}x&\text{if }x\ge0\\-x&\text{if }x$

Then $|x-1|=x-1$ if $x\ge1$ , and $|x-1|=1-x$ is $x$ . So spliting up the integral at <em>x</em> = 1, we have

$\displaystyle \int_{-1}^2|x-1|\,\mathrm dx = \int_{-1}^1(1-x)\,\mathrm dx + \int_1^2(x-1)\,\mathrm dx$

The rest is simple:

$\displaystyle \int_{-1}^2|x-1|\,\mathrm dx = \left(x-\dfrac{x^2}2\right)\bigg|_{-1}^1 + \left(\dfrac{x^2}2-x\right)\bigg|_1^2 \\\\ = \left(\left(1-\frac12\right)-\left(-1-\frac12\right)\right) + \left(\left(2-2\right)-\left(\frac12-1\right)\right) \\\\ = \boxed{\frac52}$