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Kobotan [32]
3 years ago
7

Please please help i’ll give brainliest tysm :)

Mathematics
2 answers:
cluponka [151]3 years ago
8 0

Answer:

the tank can hold 12.5 gallons when it is full

Step-by-step explanation:

Let's assume tank can hold 'x' gallons when it is full we are given

The gas gauge in a car shows it has 40% of a tank of gas

So, gas in car is and we have the car has about 5 gallons so, we can set it equal

and then we can solve for x

Multiply both sides 5

we get

So, the tank can hold 12.5 gallons when it is full

Neko [114]3 years ago
3 0

Answer:

C) Between 9 and 13

Step-by-step explanation:

If 40% is 5 gallons, then 20% is 2.5 gallons

If you multiply both by 5, you get 12.5, which is between 9 and 13

Sorry for my weird way of math

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7.9

Step-by-step explanation:

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2 years ago
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Express 6^1/4 b^3/4 c^1/4 using a radical
hodyreva [135]

Answer:

B

Step-by-step explanation:

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so answer is B

8 0
3 years ago
r. Yi buys vegetables at a market. He purchases 6 pounds of potatoes, p, and 3 pounds of onions, n, for $18. Onions cost twice a
ad-work [718]

Answer:

  • The equation 2n = p should be 2p = n.
  • The actual cost of the onions is $3.00 per pound.
  • Potatoes cost $1.50 per pound.

Step-by-step explanation:

The wording "onions cost twice as much as potatoes" is understood to mean the cost per pound of onions (n) is equal to two times the cost per pound of potatoes (2p). Then the appropriate equation would be ...

  2p = n

Then the solution is ...

  6p +3(2p) = 18

  12p = 18

  p = 18/12 = 1.50

  n = 2p = 2(1.50) = 3.00

__

The equation should be 2p = n; onions cost $3.00 per pound; potatoes cost $1.50 per pound.

5 0
3 years ago
True or false and why: if a and b are irrational, then a^b is irrational
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False


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7 0
3 years ago
A parabola has its focus at (1,2) and its directrix is y=-2. the equation of this parabola could be
Oksi-84 [34.3K]
<span>x^2/8 - x/4 + 1/8 = 0 A parabola is defined as the set of all points such that each point has the same distance from the focus and the directrix. Also the parabola's equation will be a quadratic equation of the form ax^2 + bx + c. So if we can determine 3 points on the parabola, we can use those points to calculate the desired equation. First, let's draw the shortest possible line from the focus to the directrix. The midpoint of that line will be a point on the desired parabola. Since the slope of the directrix is 0, the line will have the equation of x=1. This line segment will be from (1,2) to (1,-2) and the midpoint will be ((1+1)/2, (2 + -2)/2) = (2/2, 0/2) = (1,0). Now for the 2nd point, let's draw a line that's parallel to the directrix and passing through the focus. The equation of that line will be y=2. Any point on that line will have a distance of 4 from the directrix. So let's give it an x-coordinate value of (1+4) = 5. So another point for the parabola is (5,2). And finally, if we subtract 4 instead of adding 4 to the x coordinate, we can get a third point of 1-4 = -3. So that 3rd point is (-3,2). So we now have 3 points on the parabola. They are (1,0), (5,2), and (-3,2). Let's create some equations of the form ax^2 + bx + c = y and then substitute the known values into those equations. SO ax^2 + bx + c = y (1) a*1^2 + b*1 + c = 0 (2) a*5^2 + b*5 + c = 2 (3) a*(-3)^2 + b*(-3) + c = 2 Let's do the multiplication for those expressions. So (4) a + b + c = 0 (5) 25a + 5b + c = 2 (6) 9a - 3b + c = 2 Equations (5) and (6) above look interesting. Let's subtract (6) from (5). So 25a + 5b + c = 2 - 9a - 3b + c = 2 = 16a + 8b = 0 Now let's express a in terms of b. 16a + 8b = 0 16a = -8b a = -8b/16 (7) a = -b/2 Now let's substitute the value (-b/2) for a in expression (4) above. So a + b + c = 0 -b/2 + b + c = 0 And solve for c -b/2 + b + c = 0 b/2 + c = 0 (8) c = -b/2 So we know that a = -b/2 and c = -b/2. Let's substitute those values for a and c in equation (5) above and solve for b. 25a + 5b + c = 2 25(-b/2) + 5b - b/2 = 2 -25b/2 + 5b - b/2 = 2 2(-25b/2 + 5b - b/2) = 2*2 -25b + 10b - b = 4 -16b = 4 b = -4/16 b = -1/4 So we now know that b = -1/4. Using equations (7) and (8) above, let's calculate a and c. a = -b/2 = -(-1/4)/2 = 1/4 * 1/2 = 1/8 c = -b/2 = -(-1/4)/2 = 1/4 * 1/2 = 1/8 So both a and c are 1/8. So the equation for the parabola is x^2/8 - x/4 + 1/8 = 0 Let's test to make sure it works. First, let's use an x of 1. x^2/8 - x/4 + 1/8 = y 1^2/8 - 1/4 + 1/8 = y 1/8 - 1/4 + 1/8 = y 1/8 - 2/8 + 1/8 = y 0 = y And we get 0 as expected. Let's try x = 2 x^2/8 - x/4 + 1/8 = y 2^2/8 - 2/4 + 1/8 = y 4/8 - 1/2 + 1/8 = y 4/8 - 1/2 + 1/8 = y 1/2 - 1/2 + 1/8 = y 1/8 = y. Let's test if (2,1/8) is the same distance from both the focus and the directrix. The distance from the directrix is 1/8 - (-2) = 1/8 + 2 = 1/8 + 16/8 = 17/8 The distance from the focus is d = sqrt((2-1)^2 + (1/8-2)^2) d = sqrt(1^2 + -15/8^2) d = sqrt(1 + 225/64) d = sqrt(289/64) d = 17/8 And the distances match again. So we do have the correct equation of: x^2/8 - x/4 + 1/8 = 0</span>
4 0
3 years ago
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