X=width of a coccer pitch
2x-20=length of a soccer pitch
Area (rectangule)=length x width
We suggest this equation:
x(2x-20)=6000
2x²-20x=6000
2x²-20x-6000=0
x²-10x-3000=0
We solve this quadratic equation:
x=[10⁺₋√(100-4*1*-3000)]/2=[10⁺₋√(100+12000)]/2=
=(10⁺₋110)/2
we have two solutions:
x₁=(10-110)/2=-50, invalid solution.
x₂=(10+110)/2=60
x=60
2x-20=2(60)-20=120-20=100
Solution: the length is 100 m, and the width is 60 m.
To check:
Area=100 m*60 m=6000 m²
The twice of width is =2(60 m)=120 m,
20 m less than twice its width is: 120 m-20 m=100 m=the length.
X^2+2x^2-5x
((x^2)+2x^2)-5x
Pull the factors out
3x^2-5x=x(3x-5)
x(3x-5)
x(3x-5)*5x^2
5x(3x-5)*x^2
Final
5x^3*(3x-5)
Answer:
d is the right answer for your question
Answer:
C) The angles in a square measure 90 degrees. The rhombus has obtuse and
acute angles.
Step-by-step explanation:
