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stepladder [879]
3 years ago
10

Which expressions are differences of squares?

Mathematics
2 answers:
Ludmilka [50]3 years ago
7 0
W² - 121
Yes we can factorize this and we will get (w + 11)(w - 11)
x² + 25
Nope, we can not factorize this
n² - 50
Again, we can not factorize this
x² - 36
Yes we can and we will get (x + 6)(x -6)

This is how I would find my answer. As you can tell, completely different compare to Apocrochon's answer but we got the same answer lol.

Thus, the correct answer are : A and D



Zarrin [17]3 years ago
6 0
If an expression is the difference of two squares, it will follow this format:
(a)^{2}-(b)^{2}
where a and b are integers or variables.

1) w^{2} - 121 = (w)^{2} -( 11)^{2}
Since the expression follows the format, it's a DoTS.

2) Since the binomial has an addition sign, it isn't a DoTS.

3) n^{2}-50=(n)^{2}-(5\sqrt{2})^{2}
The second term isn't an integer, so the expression isn't a DoTS.

4) a^{2}-36=(a)^{2}-(6)^{2}
Since the expression follows the format, it's a DoTS.

Therefore, the first and fourth expressions are differences of two squares.
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<u>old:</u> $16

<u>new:</u> $20

<u>percent increase</u>

-> formula: (new-old / old) x 100

(20-16 / 16) x 100

4/16 x 100

0.25 x 100

answer: 25% increase

8 0
3 years ago
Need help ASAP!!! Please help
cestrela7 [59]
The range of a function is the set of numbers used as y-coordinates.

Let's look at the y-coordinates of the points in the graph.
There are points in the graph with all y-coordinates greater than -3.
There are points in the graph with all y-coordinates less then -3.
At exactly -3, there is no point on the graph with that y-coordinate.
We expect the graph to behave as it is shown above 7 and below -7, so the only value excluded from the y-coordinates is -3.

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8 0
3 years ago
E
AlexFokin [52]

For this case we have that by definition, the point-slope equation of a line is given by:

y-y_ {0} = m (x-x_ {0})

Where:

m: It's the slope

(x_ {0}, y_ {0}): It is a point through which the line passes

According to the statement data we have:

m = 5\\(x_ {0}, y_ {0}): (- 8,1)

Substituting we have:

y-1 = 5 (x - (- 8))

By law of signs of multiplication we have to:

- * - = +\\y-1 = 5 (x + 8)

Answer:

The requested equation is: y-1 = 5 (x + 8)

5 0
3 years ago
Answer please it’s a big exam
melomori [17]

Answer:

Solve for be is 56

Step-by-step explanation:

That the answer

4 0
3 years ago
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a plumber charges a service call fee of $25 plus $40 for each hour she works. which variable is the independent variable?
Viktor [21]
I think I'd be the $40 she charges every hour she works. If this is multiple choice mind drop-in the options
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3 years ago
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