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raketka [301]
3 years ago
9

What is the distance from point P to point Q?What is the value of n?Explain how you determined the distance from point P to poin

t Q ,and the value of n
Mathematics
1 answer:
saveliy_v [14]3 years ago
6 0

Answer:rwhTTTTTTTTTTFEWCMJNHCNYIQEWUUYRCEHAIDHNIFEWIUFHCWIQUCFNHINHFIWUECHFEIUUWHNFIUWECFEIWUHU.

Step-by-step explanation:

You might be interested in
Mr Tom shared $300 between his two sons aged 15 years and 10 years in
Sonbull [250]

Answer:

Son of 15 years $180

Son of 10 years $120

Step-by-step explanation:

15 + 10 = 25

   25          300

   15              x = 300*15/25

                    x = 180

   25          300

   10              x = 300*10/25

                    x = 120

Son of 15 years $180

Son of 10 years $120

3 0
3 years ago
Find the slope of a line given the following two points: (4, 3) and (5, 2). 1 -1 2 -2
galben [10]
Given two points; (x₁,y₁) and (x₂,y₂) the slope is:

m=(y₁-y₂) / (x₁-x₂)      or      m=(y₂-y₁) / (x₂-x₁)

In this case:
(4,3)
(5,2)

m=(5-4)/(2-3)=1/-1=-1

Answer: the slope is -1
7 0
3 years ago
Write an equation for each linear function described. Show your work. The graph of the function passes through the point (2,1),
svp [43]

Step-by-step explanation:

As

  • The graph of the function passes through the point (2,1), and
  • y increases by 4 when x increases by 1.

so

x             y

2             1

3             5

4             9

5             13

6             17

and so on

From the table:

\mathrm{Slope\:between\:two\:points}:\quad \mathrm{Slope}=\frac{y_2-y_1}{x_2-x_1}

\left(x_1,\:y_1\right)=\left(2,\:1\right),\:\left(x_2,\:y_2\right)=\left(3,\:5\right)

m=\frac{5-1}{3-2}

m=4

As the slope-intercept form of the line is

y=mx+b

putting m=4 and any point, let say (2, 1) to find y-intercept 'b'.

1=\left(4\right)2+b

8+b=1

8+b-8=1-8

b=-7

So putting b=-7 and m=4  in the slope-intercept form of the line

y=\left(4\right)x+\left(-7\right)

y=4x-7

Therefore, the equation for the linear function will be:

y=4x-7

8 0
3 years ago
A line that passes through (-1, 6) and the origin
zmey [24]

Answer: The equation is y = -6*x

Step-by-step explanation:

I suppose that we want to find the equation for a line that passes through the point (-1, 6) and the origin (remember that the origin is the point (0,0))

A general linear equation is written as:

y = a*x + b

Where a is the slope and b is the y-intercept.

If this line passes through the points (x₁, y₁) and (x₂, y₂), then the slope of the line is equal to:

a = (y₂ - y₁)/(x₂ - x₁)

Now we know that our line passes through the points (0, 0) and (-1, 6), then the slope is:

a = (6 - 0)/(-1 - 0) = 6/-1 = -6

Then our equation is something like:

y = -6*x + b

To find the value of b we can use the fact that this line passes through the point (0, 0).

This means that when x = 0, y is also equal to zero.

If we replace these values in the equation we get:

0 = -6*0 + b

0 = b

Then our equation is:

y = -6*x

7 0
3 years ago
What si the exponential form of 243
dezoksy [38]
2.43 x 10^2

Hope this helps
7 0
3 years ago
Read 2 more answers
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