Find the equation, f(x) = a(x-h)2 + k, for a parabola that passes through the point (0, 0) and has (-3, -6) as its vertex. What
is the standard form of the equation?
1 answer:
F(x) = a(x-h)²<span> + k
</span><span><u>Given that the vertex is (-3 -6):</u>
</span>f(x) = a(x + 3)² -6
<span>
<u>Given that it passes through (0.0), find a:</u>
a(0 + 3)</span>² - 6 = 0
<span>
9a - 6 = 0
9a = 6
a = 6/9 =2/3
<u>So the equation is :</u>
</span>f(x) = 2/3(x + 3)² -6
<span>
<u>Write the equation in standard form:</u>
</span>f(x) = 2/3(x² + 6x + 9) - 6
f(x) = 2/3x² + 4x + 6 - 6
f(x) = 2/3x² + 4x
<span>
Answer: </span>f(x) = 2/3x² + 4x<span>
</span>
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Answer:
x = ±√37/9
Step-by-step explanation:
x² = 37/81
√(x²) = √(37/81)
x = ± √(37)/√(81)
x = ± √37/9
Hope this helps. - M
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mark me brainliest if i right ty
F(1) = -2 because the x intercept is 1 and the y intercept is -2
