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Romashka-Z-Leto [24]
3 years ago
8

Find the equation, f(x) = a(x-h)2 + k, for a parabola that passes through the point (0, 0) and has (-3, -6) as its vertex. What

is the standard form of the equation?
Mathematics
1 answer:
Arisa [49]3 years ago
6 0
F(x) = a(x-h)²<span> + k

</span><span><u>Given that the vertex is (-3 -6):</u>

</span>f(x) = a(x + 3)² -6
<span>
<u>Given that it passes through (0.0), find a:</u>

a(0 + 3)</span>² - 6 = 0
<span>
9a - 6 = 0

9a = 6

a = 6/9 =2/3

<u>So the equation is :</u>

</span>f(x) = 2/3(x + 3)² -6
<span>
<u>Write the equation in standard form:</u>

</span>f(x) = 2/3(x² + 6x + 9) - 6

f(x) = 2/3x² + 4x + 6 - 6

f(x) = 2/3x² + 4x
<span>
Answer: </span>f(x) = 2/3x² + 4x<span>


</span>
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