$x_{1}=3 \\ \\ x_{2}=5i \\ \\ x_{2}=-5i \\ \\ f(x)=(x-x_{1})(x-x_{2})(x-x_{3})=(x-3)(x-5i)(x+5i)= \\ \\ =(x-3)(x^{2}+25)=x^{3}+25x-3x^{2}-75=x^{3}-3x^{2}+25x-75$

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6 0

3 years ago

2x + 3y = 3 and x + 6y = -3

jekas [21]

Answer:

Step-by-step explanation:

Multiplying x+6y=-3 with 2 so its equal to first eqn,

Eliminating,

2x + 3y = 3 (1)

2x +12y = -6 (2) (because subtracting)

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-9y =9

∴y=-1

eq. y in 1

2x -3=3

2x=3+3

x=6/2

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4 0

3 years ago

Which expression gives the value of x?

melisa1 [442]

15 gggggggggggggggggggggg

5 0

3 years ago

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