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Fiesta28 [93]
3 years ago
6

A digital camcorder repair service has set a goal not to exceed an average of 5 working days from the time the unit is brought i

n to the time repairs are completed. A random sample of 12 repair records showed the following repair times (in days): 5, 7, 4, 6, 7, 5, 5, 6, 4, 4, 7, 5.
H0: \mu \leq 5 days versus H1: \mu > 5 days. At \alpha = .05, choose the right option.
a) Reject H0 if tcalc < 1.7960
b) Reject H0 if tcalc >1.7960
Mathematics
1 answer:
garri49 [273]3 years ago
6 0

Answer:

The degrees of freedom first given by:  

df=n-1=12-1=11  

Then we can find the critical value taking in count the degrees of freedom and the alternative hypothesis and then we need to find a critical value who accumulates 0.05 of the area in the right tail and we got:

t_{\alpha}= 1.796

And for this case the rejection region would be:

b) Reject H0 if tcalc >1.7960

Step-by-step explanation:

Information given

5, 7, 4, 6, 7, 5, 5, 6, 4, 4, 7, 5.

System of hypothesis

We want to test if the true mean is higher than 5, the system of hypothesis are :  

Null hypothesis:\mu \leq 5  

Alternative hypothesis:\mu > 5  

The statistic is given by:

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}} (1)  

The degrees of freedom first given by:  

df=n-1=12-1=11  

Then we can find the critical value taking in count the degrees of freedom and the alternative hypothesis and then we need to find a critical value who accumulates 0.05 of the area in the right tail and we got:

t_{\alpha}= 1.796

And for this case the rejection region would be:

b) Reject H0 if tcalc >1.7960

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Negative five pi divided by two

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Any idea ? I need help
trasher [3.6K]
Use the Pythagorean Theorem:
a^2 + b^2= c^2

a= one side= 68 mi
b= second side= 80 mi
c= hypotenuse= Greenville to Columbia mi


a^2 + b^2= c^2

68^2 + 80^2= c^2
square each number

4,624 + 6,400= c^2

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104.995 mi= c


ANSWER: The distance from Greenville to Columbia is 104.995 miles (rounded to 105 miles).

Hope this helps! :)
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3 years ago
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The fence is 210 ft long.
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Here's another way of thinking of why you end up with 60 posts.
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Let q(x)=8x-7 what is q(4) a. 25 b. 36 c. 39 d. 32
zhuklara [117]
I hope this helps you



x=4 q (4)=8.4-7


q (4)=32-7


q (4)=25
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How do you solve g= y-c+x for x
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3 years ago
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