Work out the volume of a cubeboid 10cm by 3cm by 2cm

DedPeter [7]

It is the sum of the integers from 1-41 minus the sum of the integers from 1-24 divided by 17 the sum of the integers from 1-41 is (42)(45)/2 = 861 the sum of the integers from 1-24 is (24)(25)/2 = 300 (861-300)/17 = 33 The answer is 33

5 0

3 years ago

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A half-century ago, the mean height of women in a particular country in their 20s was 64.7 inches. Assume that the heights of

Ainat [17]

Answer:

99.5% of all samples of 21 of today's women in their 20's have mean heights of at least 65.86 inches.

Step-by-step explanation:

We are given that a half-century ago, the mean height of women in a particular country in their 20's was 64.7 inches. Assume that the heights of today's women in their 20's are approximately normally distributed with a standard deviation of 2.07 inches.

Also, a samples of 21 of today's women in their 20's have been taken.

Let $\bar X$ = sample mean heights

The z-score probability distribution for sample mean is given by;

Z = $\frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\mu$ = population mean height of women = 64.7 inches

$\sigma$ = standard deviation = 2.07 inches

The Z-score measures how many standard deviations the measure is away from the mean. After finding the Z-score, we look at the z-score table and find the p-value (area) associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X.

Now, Probability that the sample of 21 of today's women in their 20's have mean heights of at least 65.86 inches is given by = P( $\bar X$ $\geq$ 65.86 inches)

P( $\bar X$ $\geq$ 65.86 inches) = P( $\frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n} } }$ $\geq$ $\frac{65.86-64.7}{\frac{2.07}{\sqrt{21} } }$ ) = P(Z $\geq$ -2.57) = P(Z $\leq$ 2.57)

= 0.99492 or 99.5%

The above probability is calculated by looking at the value of x = 2.57 in the z table which has an area of 0.99492.

Therefore, 99.5% of all samples of 21 of today's women in their 20's have mean heights of at least 65.86 inches.

3 0

3 years ago

A password consists of 2 letters followed by 2 digits. How many different passwords can be formed?

kkurt [141]

There are 26 letters. There are 10 digits. Different combos possible are 26 * 26 * 10 * 10

Basically 67,600 different passwords can be formed. Rate and Thank if helped! :)

7 0

3 years ago

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CAN SOMEONE FACTOR THIS PLEASE 125х^6 - 81

alexandr402 [8]

Answer:

0

Step-by-step explanation:

125×^6_81=0

×^6 we do not support this expression

ans = 0

3 0

2 years ago

write a real-world problem in which you would need to find the number of units between -6 and 0 on a number line.

Mariulka [41]

Sam started with 0 dollars in his bank account. He charged his debit card for a sandwich that costs $6.00. If this was written on a number line. How many units would Sam to go to get back to where he started?

4 0

3 years ago