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Advocard [28]
3 years ago
15

Solve the following x squared equal 49 (x2 = 49)

Mathematics
1 answer:
wariber [46]3 years ago
4 0

Answer:

x = 7

Step-by-step explanation:

7^2 or 7*7 = 49

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A playground merry-go-round of radius R = 1.80 m has a moment of inertia I = 255 kg · m2 and is rotating at 9.0 rev/min about a
Degger [83]

Answer:

7 rpm = 0.73 rad/s

Step-by-step explanation:

R = Radius of merry-go-round = 1.8 m

I_M= Moment of inertia of merry-go-round = 255 kg m²

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From the conservation of angular momentum

I\omega=I'\omega '\\\Rightarrow I\omega=(I_M+I_C)\omega'\\\Rightarrow \omega'= \frac{I\omega}{(I_M+I_C)}\\\Rightarrow \omega'=\frac{I\omega}{(I_M+mR^2)}\\\Rightarrow \omega'=\frac{255\times 9}{(255+24\times 1.8^2)}\\\Rightarrow \omega'=6.9\ rev/min

∴ New angular speed of the merry-go-round is 7 rpm = 7\times \frac{2\pi}{60}=\mathbf{0.73\ rad/s}

3 0
4 years ago
Please help meee with my math i am so confused!!! Thank youuuu
Rudik [331]

Answer:


Step-by-step explanation:

x decreases w/o bound, so x becomes a very large -ve no.

f(x)=5^(x-1) becomes 5^(large -ve no.) which will be almost zero


x increases w/o bound, so x becomes a very large +ve no.

f(x)=5^(x-1) becomes 5^(large +ve no.) which will keep increasing w/o bound


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