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Tasya [4]
2 years ago
14

An online T-shirt store is having a sale. The original price of each T-shirt is p dollars. The store sells 20 T-shirts and earns

a total of (20p−60) dollars.
a. Factor the expression using the GCF.

20p−60=
Mathematics
2 answers:
Mrac [35]2 years ago
4 0
20p - 60 = 20p - 3*20 = 20(p-3)
aleksandr82 [10.1K]2 years ago
4 0

20p - 60 = 20p - 3*20 = 20(p-3)


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3) gentry is training for a marathon. she increases the amount of time she runs by 5 mins. each day to build up her endurance. o
nika2105 [10]
Y=5x+30

X is the days

And so by plugging in x you get

y=5(5)+30
y=25+30
y=55

And so by day 5 she's running 55 minutes

But that's what I think
3 0
3 years ago
Several programs attempt to address the shortage of qualified teachers by placing uncertified instructors in schools with acute
ss7ja [257]

Answer:

We conclude that the mean scores with uncertified teachers is higher or equal as compared to certified teachers.

Step-by-step explanation:

We are given that reading scores of the students of certified teachers averaged 35.62 points with standard deviation 9.31. The scores of students instructed by uncertified teachers had mean 32.48 points with standard deviation 9.43 points on the same test.

There were 44 students in each group.

Let \mu_1 = <em><u>mean scores with uncertified teachers.</u></em>

\mu_2 = <em><u>mean scores with certified teachers.</u></em>

So, Null Hypothesis, H_0 : \mu_1\geq \mu_2     {means that the mean scores with uncertified teachers is higher or equal as compared to certified teachers}

Alternate Hypothesis, H_A : \mu_1     {means that the mean scores with uncertified teachers is lower as compared to certified teachers}

The test statistics that would be used here <u>Two-sample t test statistics</u> as we don't know about the population standard deviations;

                          T.S. =  \frac{(\bar X_1-\bar X_2)-(\mu_1-\mu_2)}{s_p\sqrt{\frac{1}{n_1} +\frac{1}{n_2} } }  ~ t__n__1-_n__2-2

where, \bar X_1 = sample mean scores of students instructed by uncertified teachers = 32.48 points

\bar X_2 = sample mean scores of students instructed by certified teachers = 35.62 points

s_1 = sample standard deviation of scores of students instructed by uncertified teachers = 9.43 points

s_2 = sample standard deviation of scores of students instructed by certified teachers = 9.31 points

n_1 = sample of students under uncertified teachers = 44

n_2 = sample of students under certified teachers = 44

Also,  s_p=\sqrt{\frac{(n_1-1)s_1^{2} +(n_2-1)s_2^{2} }{n_1+n_2-2} } = \sqrt{\frac{(44-1)\times 9.43^{2} +(44-1)\times 9.31^{2} }{44+44-2} } = 9.37

So, <u><em>the test statistics</em></u>  =  \frac{(32.48-35.62)-(0)}{9.37 \times \sqrt{\frac{1}{44} +\frac{1}{44} } }  ~ t_8_6

                                     =  -1.572

The value of t test statistics is -1.572.

Since, in the question we are not given the level of significance so we assume it to be 5%. <u>Now, at 5% significance level the t table gives critical values of -1.665 at 86 degree of freedom for left-tailed test.</u>

Since our test statistic is more than the critical values of t as -1.572 > -1.665, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which <u>we fail to reject our null hypothesis</u>.

Therefore, we conclude that the mean scores with uncertified teachers is higher or equal as compared to certified teachers.

7 0
2 years ago
The daily cost of hiring a plumber, y, to work hours on a repair project can be modeled
Alex73 [517]

Answer:

  [50, 410]

Step-by-step explanation:

If the plumber works 0 hours, he still charges $50, so that is the minimum of the range of charges.

If the plumber works 8 hours, his hourly charge of 8×$45 = $360 is added to his fixed charge of $50 for a total of $410. That is the maximum of the range of daily charges.

The range of the function is $50 to $410.

4 0
3 years ago
Eliminate 3x+2y=4<br> 8x-3y=-6
laila [671]
Steps:
1. Multiply the first line by 3 and the second by 2
3(3x + 2y= 4)
2(8x -3y=-6)
2. New lines are
9x + 6y= 12
16x + -6y=-12
3. Now add/subtract them
25x + 0= 0
25x=0
4. Divide by 25
X=0

5. To find y, substitute the 0 in the x in one of the equations
9x + 6y= 12
9(0) + 6y= 12
6y= 12
6. Divide by 6, your Y=2
7. X=0, Y=2
7 0
3 years ago
Fill the missing values to make the equations true.
taurus [48]
Logarithm properties:

\displaystyle \log_a b+\log_a c=\log_a (b\cdot c)\\\\\log_ab-\log_a c=\log_a \left( \frac{b}{c} \right)\\\\\log_{a^p}b^q= \frac{q}{p} \log_a b

According to this, we can get:

\displaystyle a)\log_7 3+\log_7 8=\log_7 (3\cdot 8)=\log_724\\\\b) \log_89-\log_85=\log_8  \frac{9}{5}\\\\c)\log_325=2\log_35
3 0
3 years ago
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