A computer software retailer used a mark up of 150%. Find the cost of the computer

David’s bank offers a 36-month Certificate of Deposit (CD) with an APR of 2.25%. Use the compound interest formula to answer the

tamaranim1 [39]

Using compound interest, it is found that:

a) A(8) = 2389.66

b) t = 31.15

c) P = 1870.85

Compound interest:

$A(t) = P\left(1 + \frac{r}{n}\right)^{nt}$

A(t) is the amount of money after t years.
P is the principal(the initial sum of money).
r is the interest rate(as a decimal value).
n is the number of times that interest is compounded per year.
t is the time in years for which the money is invested or borrowed.

In this problem:

The APR is of 2.25%, hence $r = 0.0225$ .

No information about the number of compounding per year, hence $n = 1$ .

Item a:

$P = 2000$ , hence:

$A(t) = P\left(1 + \frac{r}{n}\right)^{nt}$

$A(8) = 2000\left(1 + \frac{0.0225}{1}\right)^{8}$

$A(8) = 2389.66$

Item b:

$A(t) = 4000$ , hence:

$A(t) = P\left(1 + \frac{r}{n}\right)^{nt}$

$4000 = 2000\left(1 + \frac{0.0225}{1}\right)^{t}$

$(1.0225)^t = 2$

$\log{(1.0225)^t} = \log{2}$

$t\log{1.0225} = \log{2}$

$t = \frac{\log{2}}{\log{1.0225}}$

$t = 31.15$

Item c:

$A(3) = 2000$ , hence:

$A(t) = P\left(1 + \frac{r}{n}\right)^{nt}$

$2000 = P\left(1 + \frac{0.0225}{1}\right)^{3}$

$P = \frac{2000}{(1.0225)^3}$

$P = 1870.85$

A similar problem is given at brainly.com/question/24850750

7 0

2 years ago

The blood platelet counts of a group of women have a bell-shaped distribution with a mean of 256.3 and a standard deviation of

AnnyKZ [126]

Answer:

a) In the interval ( 55,9 ; 456,7 ) we will find 99,7 % of all values

b) In the interval ( 122,7 ; 389,9 ) we find 95,4 % of all values

Step-by-step explanation:

For a Normal distribution N (μ ; σ ) the Empirical rule establishes that the intervals:

( μ ± σ ) contains 68,3 % of all values

( μ ± 2σ ) contains 95,4 % of all values

( μ ± 3σ ) contains 99,7 % of all values

If N ( 256,3 ; 66,8 )

σ = 66,8 ⇒ 3*σ = 3 * 66,8 = 200,4

Then: 256,3 - 200,4 = 55,9

And 256,3 + 200,4 = 456,7

a) In the interval ( 55,9 ; 456,7 ) we will find 99,7 % of all values

b) 2*σ = 2 * 66,8 = 133,6

Then 256,3 - 133,6 = 122,7

And 256,3 + 133,6 = 389,90

Then in the interval ( 122,7 ; 389,9 ) we find 95,4 % of all values

4 0

3 years ago

A poster has a width of (w+2) feet and an area of (2w+4) square feet. Your answers must include units

Solnce55 [7]

Answer:

Length=2

Step-by-step explanation:

(2w+4)/(w+2)=2

8 0

3 years ago

Heather, a sociology major is interested in studying mass media topics. She is particularly interested in the percentage of mass

Serhud [2]

Answer:

Null hypothesis: $p=0.72$

Alternative hypothesis: $p \neq 0.72$

$p_v = 2*P(|z|>z_{calc})$

And the best answer for this case is:

C. p-value

Step-by-step explanation:

Data given and notation

n represent the random sample taken

$\hat p$ estimated proportion of interest

$p_o=0.72$ is the value that we want to test

$\alpha=0.05$ represent the significance level

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that the true proportion i 0.72 or no.:

Null hypothesis: $p=0.72$

Alternative hypothesis: $p \neq 0.72$

When we conduct a proportion test we need to use the z statistic, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

For this case the only probability that can be calculated from the statistic calculated is the p value given by:

$p_v = 2*P(|z|>z_{calc})$

And the best answer for this case is:

C. p-value

3 0

3 years ago

How many tattoos does Niall Horan have?

kaheart [24]

Answer:

none

Step-by-step explanation:

he works for one direction.

4 0

3 years ago

Read 2 more answers