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KonstantinChe [14]
3 years ago
12

HELP IM STRUGGLING I DONT WANNA FAIL THIS SCHOOL YEAR

Mathematics
1 answer:
mixer [17]3 years ago
5 0

Answer:

507 cubic m

Step-by-step explanation:

V = l · w · h

V = 13 × 13 × 3

V = 507

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40% of the students in a school band play brass instruments while 4 students play strings instruments
MaRussiya [10]
10 students (brass)=40% of band
4 students (strings)=16% of band 
? students (other)=44% rest of band
14/56%=?/44%
(cross multiply to find ?){don't forget to turn percents into decimals}
?=11
There are 25 students in total in the band.

5 0
3 years ago
Area of a trapezium​
melamori03 [73]

Answer:

The area of a trapezium is computed with the following formula: Area = 1 2 × Sum of parallel sides × Distance between them.

Step-by-step explanation:

Hope it help! :)

7 0
2 years ago
Read 2 more answers
Sketch the region enclosed by the given curves. Decide whether to integrate with respect to x or y. Then find the area of the re
mina [271]

Answer:

Step-by-step explanation:

integrate with respect to x

Area is symmetric so will be twice the integral from zero to 1

( I cannot seem to figure out how to make the lower limit negative in this editor)

A = 2\int\limits^1_0 {(x^2 + 3) - 4x^2} \, dx)

A = 2\int\limits^1_0 {-3x^2 + 3} \, dx

A = 6\int\limits^1_0 {-x^2 + 1} \, dx

A = 6(-⅓x³ + x)\left \| {{x=1} \atop {x=0}} \right.

A = 6((-⅓(1)³ + (1)) - (-⅓(0)³ + (0)))

A = 6(⅔)

A = 4 units²

7 0
2 years ago
Two similar triangles have areas of 18 and 32 find the ratio of their perimeters
tia_tia [17]
\bf \qquad \qquad \textit{ratio relations}
\\\\
\begin{array}{ccccllll}
&Sides&Area&Volume\\
&-----&-----&-----\\
\cfrac{\textit{similar shape}}{\textit{similar shape}}&\cfrac{s}{s}&\cfrac{s^2}{s^2}&\cfrac{s^3}{s^3}
\end{array} \\\\
-----------------------------\\\\
\cfrac{\textit{similar shape}}{\textit{similar shape}}\qquad \cfrac{s}{s}=\cfrac{\sqrt{s^2}}{\sqrt{s^2}}=\cfrac{\sqrt[3]{s^3}}{\sqrt[3]{s^3}}\\\\
-------------------------------\\\\

\bf \cfrac{smaller}{larger}\qquad \cfrac{s^2}{s^2}=\cfrac{18}{32}\implies \left( \cfrac{s}{s} \right)^2=\cfrac{18}{32}\implies \cfrac{s}{s}=\sqrt{\cfrac{18}{32}}
\\\\\\
\cfrac{s}{s}=\cfrac{\sqrt{18}}{\sqrt{32}}\implies \cfrac{s}{s}=\cfrac{\sqrt{9\cdot 2}}{\sqrt{16\cdot 2}}\implies \cfrac{s}{s}=\cfrac{\sqrt{3^2\cdot 2}}{\sqrt{4^2\cdot 2}}\implies \cfrac{s}{s}=\cfrac{3\sqrt{2}}{4\sqrt{2}}
\\\\\\
\cfrac{s}{s}=\cfrac{3}{2}
6 0
3 years ago
Solve pls brainliest
Andreyy89

Answer:

1. 9

2. 5

Step-by-step explanation:

3 0
3 years ago
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