Question

2) You have a bag of chocolate candy. Ten of them are red, 7 are brown, 12 are green, and 9 are blue. What is the probability that you pick a red candy, given that you have already picked a red candy and have not replaced

Answer 1

Answer:

$\frac{9}{37}$ or %24

Step-by-step explanation:

Since you have already took a red candy and didn't replace it the normal $\frac{10}{38}$ would be replaced with $\frac{9}{37}$.

To find this you need to add all the candies together and find the number of specific candies you want, in this case red/9.

Now put the 9 above the total number as a fraction.

In order to find the percent divide 9 by 37

9/37=0.243243243

Simplify it 0.24

Now move the . over to the right two times!

24%!