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Neporo4naja [7]

3 years ago

8

Y=(

la1" title="y = ( \sqrt{x + 3} + 5) ^{10 } " alt="y = ( \sqrt{x + 3} + 5) ^{10 } " align="absmiddle" class="latex-formula">

1 answer:

MA_775_DIABLO [31]3 years ago

3 0

Answer:

(-8,0)

Step-by-step explanation:

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An observer (O) spots a plane flying at a 42° angle to his horizontal line of sight. If the plane is flying at an altitude of 15

NeTakaya

Answer:

D. 22,417 feet

Step-by-step explanation:

Fine the diagram in the attachment for proper elucidation. Using the SOH, CAH, TOA trigonometry identity to solve for the distance (x) from the plane (P) to the observer (O), the longest side x is the hypotenuse and the side facing the angle of elevation is the opposite.

Hypotenuse = x and Opposite = 15,000feet

According to SOH;

$sin 42^0 = \frac{Opposite}{Hypotenuse} \\\\Sin42^0 = \frac{15000}{x}\\ \\x = \frac{15000}{sin42^0}\\\\ \\$

$x = \frac{15000}{ 0.6691} \\\\x = 22,417 feet$

Hence the distance (x) from the plane P to the observer O is approximately 22,417 feet

3 0

4 years ago

which of the following answer choices describes all the transformation found in the cubic function f(x)=-(x+2)3-5

Alona [7]

The cubic function is f(x) = x^3

You need to perform three transformations to the cubic function to obtain
f(x) = - (x + 2)^3 - 5.

Those transfformations are:

1) Shift f(x) = x^3, 2 units leftward to obtain f(x) = (x + 2)^3

2) reflect f(x) = (x + 2)^3 across the x-axis to obtain f(x) = - (x + 2)^3

3) shift f(x) = - ( x + 2) ^3, 5 units downward to obtain f(x) = - (x + 2)^3 - 5

8 0

4 years ago

.0000458 put this in scientific notation

amm1812

4.58 x 10^-5

hope I helped

3 0

3 years ago

Identify the correct corresponding parts

andrey2020 [161]

Answer:

The correct corresponding part is;

$\overline {CB}$ ≅ $\overline {CD}$

Step-by-step explanation:

The information given symbolically in the diagram are;

ΔCAB is congruent to ΔCED (ΔCAB ≅ ΔCED)

Segment $\overline {CA}$ is congruent to $\overline {CE}$ ( $\overline {CA}$ ≅ $\overline {CE}$ )

Segment $\overline {CB}$ is congruent to $\overline {CD}$ ( $\overline {CB}$ ≅ $\overline {CD}$ )

From which, we have;

∠A ≅ ∠E by Congruent Parts of Congruent Triangles are Congruent (CPCTC)

∠B ≅ ∠D by CPCTC

Segment $\overline {AB}$ is congruent to $\overline {DE}$ ( $\overline {AB}$ ≅ $\overline {DE}$ ) by CPCTC

Segment $\overline {AE}$ bisects $\overline {BD}$

Segment $\overline {BD}$ bisects $\overline {AE}$

Therefore, the correct option is $\overline {CB}$ ≅ $\overline {CD}$

3 0

3 years ago

3. Six neighborhood children - Leisha, Benito, Delia, Charlotte, Weldon, and Zina- were measured

sergij07 [2.7K]

Zina, weldon, delia, leisha, bento, charlotte

8 0

3 years ago