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Damm [24]
3 years ago
15

In bowling, knocking down all of the pins with the first ball of a frame is called a strike. Roni is practicing bowling and gets

a strike times out of attempts. Her goal is to have a minimum strike rate of . Which inequality could Roni use to determine the minimum number of consecutive strikes she needs to achieve her goal?
Mathematics
1 answer:
Nesterboy [21]3 years ago
5 0

Answer:

0.50 \leq \frac{x+2}{x+10}\\

At least 6 strikes

Step-by-step explanation:

The required numerical data is missing from the question. In the original question, Roni gets a strike 2 out of 10 times and her goal is to have a minimum strike rate of 50%. The number of consecutive strikes required is given by the following inequality:

0.50 \leq \frac{x+2}{x+10}\\

Solving the inequality:

0.5x+5 \leq x+2\\3\leq0.5x\\x\geq6

Roni needs at least 6 strikes.

After 6 strikes, she would have 8 out of 16, which equals exactly 50%.

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3 years ago
Give examples of where the cubic decimeter is used around us?
pogonyaev

Answer:

A unit of volume equal to that of a cube having sides each one decimetre in length, equal to 10-3 cubic metres and 1 litre. Commonly used in fluid measure and for engine sizes.

3 0
3 years ago
The table gives estimates of the world population, in millions, from 1750 to 2000. (Round your answers to the nearest million.)
BaLLatris [955]

Answer:

A.) 1508 ; 1870

B.) 2083

C.) 3972

Step-by-step explanation:

General form of an exponential model :

A = A0e^rt

A0 = initial population

A = final population

r = growth rate ; t = time

1)

Using the year 1750 and 1800

Time, t = 1800 - 1750 = 50 years

Initial population = 790

Final population = 980

Let's obtain the growth rate :

980 = 790e^50r

980/790 = e^50r

Take the In of both sides

In(980/790) = 50r

0.2155196 = 50r

r = 0.2155196/50

r = 0.0043103

Using this rate, let predict the population in 1900

t = 1900 - 1750 = 150 years

A = 790e^150*0.0043103

A = 790e^0.6465588

A = 1508.0788 ; 1508 million people

In 1950;

t = 1950 - 1750 = 200

A = 790e^200*0.0043103

A = 790e^0.86206

A = 1870.7467 ; 1870 million people

2.)

Exponential model. For 1800 and 1850

Initial, 1800 = 980

Final, 1850 = 1260

t = 1850 - 1800 = 50

Using the exponential format ; we can obtain the rate :

1260 = 980e^50r

1260/980 = e^50r

Take the In of both sides

In(1260/980) = 50r

0.2513144 = 50r

r = 0.2513144/50

r = 0.0050262

Using the model ; The predicted population in 1950;

In 1950;

t = 1950 - 1800 = 150

A = 980e^150*0.0050262

A = 980e^0.7539432

A = 2082.8571 ; 2083 million people

3.)

1900 1650

1950 2560

t = 1900 - 1950 = 50

Using the exponential format ; we can obtain the rate :

2560 = 1650e^50r

2560/1650 = e^50r

Take the In of both sides

In(2560/1650) = 50r

0.4392319 = 50r

r = 0.4392319/50

r = 0.0087846

Using the model ; The predicted population in 2000;

In 2000;

t = 2000 - 1900 = 100

A = 1650e^100*0.0087846

A = 1650e^0.8784639

A = 3971.8787 ; 3972 million people

3 0
3 years ago
If m 1=55, what is m 5?
AleksAgata [21]
275 if i'm not mistaken
6 0
3 years ago
Read 2 more answers
(2<br> 2X 2<br> −3 ÷ 2<br> 5<br> )<br> 2 =
Pavlova-9 [17]

Answer

Extract form = 2194 /25

Decimal form =87.76

4 0
3 years ago
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