15-b=4b-5(5-3)
Multiply the bracket by -5
(-5)(5)=-25
(-5)(-3)=15
15-b=4b-25+15
15-b=4b-10
Move 15 to the other side
Sign changes from +15 to -15
15-15-b=4b-10-15
-b=4b-25
Move 4b to the other side.
-b-4b=4b-4b-25
-b-4b=-25
-5b=-25
divide both sides by -5
-5b/-5=-25/-5
Answer: b=5
Answer:
The correct answer is 47.5%, or 0.475.
Step-by-step explanation:
Answer:
3.16 units
Step-by-step explanation:
It has been given that the triangles JKL and the triangle RST are congruent.
That implies that, the length of the side JK, KL, and JL is equivalent to the length of the sides RS, ST, and RT respectively.
Now, to find the length of JK we need to find the length of the side RS. The coordinates of the points R and S are
and
.
The length of the side RS is equal to the distance between point R and S.
RS 



Now that we have the length of the side RS, and the triangles JKL and RST are congruent therefore, the length of the side JK is 3.16 units.
<h3>Answer 1a :- </h3>
Here we can solve this question using<em> </em><em>Unitary</em><em> </em><em>Method</em><em> </em><em>.</em> As ;
→ In 17hrs the boat travels 452km
→ In 1hr the boat will travel 452km/17
→ In 9hrs the boat will travel 452/17km * 9 = 239.29km

<h3>Answer 1b:-</h3>
→ A car can travel 156km on 13L gasoline .
→ It will travel 1km on 13/156L of gasoline .
→ It will travel 480km on 13/156*480L = 40L of gasoline .

<h3>
Answer 2a :-</h3>
→ A boat can go 180 miles on 60L gasoline.
→ It will go 1mile in 60/180L of gasoline.
→ It will go 306 miles in 60/180*306L = 102L of gasoline .

<h3>Answer 2b :-</h3>
→ On 51L of gasoline a car can go 408km
→ On 1L of gasoline car will go 408/51 km
→ On 11L of gasoline it will go 408/51*11L = 88km
