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zalisa [80]
3 years ago
12

Help help please!!

Mathematics
1 answer:
andrey2020 [161]3 years ago
6 0

Answer:

1). y = -7/5x - 4

2). y = 1/5x - 5

Step-by-step explanation:

In this question, we have to write the slope-intercept form of the given information.

Slope intercept form is: y = mx + b

Our "m" value is our slope and our "b" value is our y-intercept.

With that knowledge, we can plug in our given information to the slope-intercept equation:

1) slope = -7/5, y-intercept = -4

Plug -7/5 to "m" and -4 to "b"

y = -7/5x - 4

2) slope = 1/5, y-intercept = -5

Plug 1/5 to "m" and -5 to "b"

y = 1/5x - 5

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Draw the graph of f(x) = (x − 1)2 − 2. Start by creating a table of ordered pairs for the function. Then plot the points from th
pogonyaev

The attached graph represents the graph of f(x) = (x - 1)^2 - 2

<h3>How to plot the graph?</h3>

The equation is given as:

f(x) = (x - 1)^2 - 2

Next, we set x to -2, -1, 0, 1 and 2.

So, we have:

f(-2) = (-2 - 1)^2 - 2 = 7

f(-1) = (-1 - 1)^2 - 2 = 2

f(0) = (0 - 1)^2 - 2 = -1

f(1) = (1 - 1)^2 - 2 = -2

f(2) = (2 - 1)^2 - 2 = -1

This means that the table of values is

x      f(x)

-2    7

-1    2

0    -1

1     -2

2    -1

Next, we plot the above points and connect them.

See attachment for the graph of f(x) = (x - 1)^2 - 2

Read more about graphs and functions at:

brainly.com/question/4025726

#SPJ1

7 0
1 year ago
The table below shows data from a survey about the amount of time students spend doing homework each week. The students were in
nadezda [96]

Answer:

The correct option is;

Both spreads are best described by the standard deviation

Step-by-step explanation:

The given information are;

,                                    College                       High School

High,                              20                               20

Low,                                6                                 3

Q₁,                                   8                                 5.5

Q₃,                                  18                                16

IQR,                                 10                                10.5

Median,                           14                                11

Mean,                              13.3                             11

σ,                                      5.2                             5.4

Checking for outliers, we have

College

Q₁ - 1.5×IQR gives 8 - 1.5×10 = -7

Q₃ + 1.5×IQR gives 18 + 1.5×10 = 33

For high school

Q₁ - 1.5×IQR gives 5.5 - 1.5×10.5 = -10.25

Q₃ + 1.5×IQR gives 16 + 1.5×10.5 = 31.75

Therefore, there are no outliers and the data is representative of the population

From the data, for the college students, it is observed that the difference between the mean, 13.3 and Q₁, 8, and between Q₃, 18 and the mean,13.3 is approximately the standard deviation, σ, 5.2

The difference between the low and the high is also approximately 3 standard deviations

Therefore the college spread is best described by the standard deviation

Similarly for the high school students, the IQR is approximately two standard deviations, the  difference between the mean, 11 and Q₁, 5.5, and between Q₃, 16 and the mean,11 is approximately the standard deviation, σ, 5.4

Therefore the high school spread is also best described by the standard deviation.

4 0
2 years ago
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siniylev [52]
It will be secx = 2
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3 years ago
Which number is not greater than 0.6
polet [3.4K]
0-0.59 because the number has to be less than 0.6 and all numbers up to 0.59 are not greater than 0.6
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2 years ago
Rob notices that 55 percent of the people leaving the supermarket chhose plastic bags instead of paper bags. out of 600 people,
Bumek [7]
To solve this answer, you are trying to find 55% of 600, because that is the number of people who chose plastic bag.

55% can be re-written as 55/100 OR 0.55 since percentages are always out of 100.

So, we do 0.55*600, which gives us 330. 330 people carry plastic bags.
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3 years ago
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