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3 years ago

Help help please!!

Mathematics

1 answer:

andrey2020 [161]3 years ago

6 0

Answer:

1). y = -7/5x - 4

2). y = 1/5x - 5

Step-by-step explanation:

In this question, we have to write the slope-intercept form of the given information.

Slope intercept form is: y = mx + b

Our "m" value is our slope and our "b" value is our y-intercept.

With that knowledge, we can plug in our given information to the slope-intercept equation:

1) slope = -7/5, y-intercept = -4

Plug -7/5 to "m" and -4 to "b"

y = -7/5x - 4

2) slope = 1/5, y-intercept = -5

Plug 1/5 to "m" and -5 to "b"

y = 1/5x - 5

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8.75*32.5=284.375 this week

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2 years ago

Brian's gross earnings for the week of July 8, 2019, are $1227.38. His deductions comprise 23% of his total compensation.

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Answer:

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3 years ago

Solve the system of equations below by using the elimination or substitution method.

pashok25 [27]

Answer: this is the answer

Step-by-step explanation:

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3 years ago

Use the discriminate to determine the number and the nature of the solutions of the giving equation.

PolarNik [594]

Answer:

Since b^2 -4ac = 256 we have 2 real distinct root roots

Step-by-step explanation:

4x^2+12x=7

We need to subtract 7 to get it in the proper form

4x^2+12x-7=7-7

4x^2+12x-7=0

The discriminant is b^2 -4ac

when the equation is ax^2 +bx+c

so a =4 b=12 and c=-7

(12)^2 - 4(4)(-7)

144 +112

256

If b^2 -4ac > 0 we have 2 real distinct roots

If b^2 -4ac = 0 we have one real root

If b^2 -4ac < 0 we have two complex root

Since b^2 -4ac = 256 we have 2 real distinct root roots

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3 years ago

7. A kite in the shape of a square with a diagonal 32 cm and an isosceles triangle of base 8 cm and sides 6 cm each is to be mad

grin007 [14]

Answer:

Step-by-step explanation:

diagonal = 32 cm

Area of square = $\dfrac{d^{2}}{2}$

$=\dfrac{32*32}{2}\\\\=512 \ cm^{2}$

Diagonal separate the square into two equal triangles.

Area of upper triangle that is shaded black = area of lower triangle = 512/2

= 256 cm²

Isosceles triangle:

a = 6 cm ; b = 6 cm c = 8cm

$s = \dfrac{a+b+c}{2}\\\\=\dfrac{6+6+8}{2}\\\\=\dfrac{20}{2}\\\\=10\\\\s-a = 10 - 6 = 4 \ cm\\\\s-b = 10-6 = 4 \ cm\\\\c - c = 10 - 8 = 2 \ cm\\\\Area = \sqrt{s*(s-a)(s-b)(s-c)}\\\\=\sqrt{10*4*4*2}\\\\=\sqrt{2 * 2 * 4 * 4 * 5}\\\\=4*2\sqrt{5}\\\\=8\sqrt{5}\\\\=8*2.24\\\\=17.92 \ cm^{2}$

Area of black shade paper = 256 + 17.92 = 273.92 cm²

Area of white shade paper = 256 cm²

Area of the isosceles triangle = s(s-a)(s-b)(s-c)

7 0

3 years ago