HELP ASAP!!! math problem 50 points!!!

Help me please I can’t do this anymore it’s so hard

never [62]

Answer:

2

Step-by-step explanation:

Don't really know how to explain it. OmniCalculator is very helpful.

Hope that this helps!

6 0

3 years ago

The sum of two consecutive cube numbers is 341. Work out the two numbers. (2 marks)

Kobotan [32]

Answer:

63 and 53

Step-by-step explanation:

you could use trail and error. So:

13+23=9

33+43=91

63+73=559

53+63=341

3 0

3 years ago

Find all the solutions for the equation:

Contact [7]

$2y^2\,\mathrm dx-(x+y)^2\,\mathrm dy=0$

Divide both sides by $x^2\,\mathrm dx$ to get

$2\left(\dfrac yx\right)^2-\left(1+\dfrac yx\right)^2\dfrac{\mathrm dy}{\mathrm dx}=0$

$\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{2\left(\frac yx\right)^2}{\left(1+\frac yx\right)^2}$

Substitute $v(x)=\dfrac{y(x)}x$ , so that $\dfrac{\mathrm dv(x)}{\mathrm dx}=\dfrac{x\frac{\mathrm dy(x)}{\mathrm dx}-y(x)}{x^2}$ . Then

$x\dfrac{\mathrm dv}{\mathrm dx}+v=\dfrac{2v^2}{(1+v)^2}$

$x\dfrac{\mathrm dv}{\mathrm dx}=\dfrac{2v^2-v(1+v)^2}{(1+v)^2}$

$x\dfrac{\mathrm dv}{\mathrm dx}=-\dfrac{v(1+v^2)}{(1+v)^2}$

The remaining ODE is separable. Separating the variables gives

$\dfrac{(1+v)^2}{v(1+v^2)}\,\mathrm dv=-\dfrac{\mathrm dx}x$

Integrate both sides. On the left, split up the integrand into partial fractions.

$\dfrac{(1+v)^2}{v(1+v^2)}=\dfrac{v^2+2v+1}{v(v^2+1)}=\dfrac av+\dfrac{bv+c}{v^2+1}$

$\implies v^2+2v+1=a(v^2+1)+(bv+c)v$

$\implies v^2+2v+1=(a+b)v^2+cv+a$

$\implies a=1,b=0,c=2$

Then

$\displaystyle\int\frac{(1+v)^2}{v(1+v^2)}\,\mathrm dv=\int\left(\frac1v+\frac2{v^2+1}\right)\,\mathrm dv=\ln|v|+2\tan^{-1}v$

On the right, we have

$\displaystyle-\int\frac{\mathrm dx}x=-\ln|x|+C$

Solving for $v(x)$ explicitly is unlikely to succeed, so we leave the solution in implicit form,

$\ln|v(x)|+2\tan^{-1}v(x)=-\ln|x|+C$

and finally solve in terms of $y(x)$ by replacing $v(x)=\dfrac{y(x)}x$ :

$\ln\left|\frac{y(x)}x\right|+2\tan^{-1}\dfrac{y(x)}x=-\ln|x|+C$

$\ln|y(x)|-\ln|x|+2\tan^{-1}\dfrac{y(x)}x=-\ln|x|+C$

$\boxed{\ln|y(x)|+2\tan^{-1}\dfrac{y(x)}x=C}$

7 0

3 years ago

Tual School

Lady_Fox [76]

Answer:

The absolute value equation to represent the scenario is |x - 250| = 25. Also, the minimum amounts and maximum amounts that the artist received for her products is $225 and $275 respectively.

What is an equation?

An equation is an expression that shows the relationship between two or more variables and numbers.

Let x represent the amount the artist can receive for the goods, hence:

|x - 250| = 25

x - 250 = 25 or -(x - 250) = 25

x = 275 or x = 225

The absolute value equation to represent the scenario is |x - 250| = 25. Also, the minimum amounts and maximum amounts that the artist received for her products is $225 and $275 respectively.

5 0

2 years ago

Need help with this I'm on a time limit

OverLord2011 [107]

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-Brainly support team (Klara academic DEPT.)Spam words mean team is having trouble determining the question CONTACT For support. Thanks for using brainly.

7 0

2 years ago