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4vir4ik [10]
3 years ago
12

What is the solution to the equation 13.7y – 10.6 = 6.2y + 19.4?  

Mathematics
2 answers:
sladkih [1.3K]3 years ago
7 0

Answer:

4   I did the assignment

Step-by-step explanation:

Lyrx [107]3 years ago
4 0

Answer:

4

Step-by-step explanation:

Simplifying

13.7y + -10.6 = 6.2y + 19.4

Reorder the terms:

-10.6 + 13.7y = 6.2y + 19.4

Reorder the terms:

-10.6 + 13.7y = 19.4 + 6.2y

Solving

-10.6 + 13.7y = 19.4 + 6.2y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-6.2y' to each side of the equation.

-10.6 + 13.7y + -6.2y = 19.4 + 6.2y + -6.2y

Combine like terms: 13.7y + -6.2y = 7.5y

-10.6 + 7.5y = 19.4 + 6.2y + -6.2y

Combine like terms: 6.2y + -6.2y = 0.0

-10.6 + 7.5y = 19.4 + 0.0

-10.6 + 7.5y = 19.4

Add '10.6' to each side of the equation.

-10.6 + 10.6 + 7.5y = 19.4 + 10.6

Combine like terms: -10.6 + 10.6 = 0.0

0.0 + 7.5y = 19.4 + 10.6

7.5y = 19.4 + 10.6

Combine like terms: 19.4 + 10.6 = 30

7.5y = 30

Divide each side by '7.5'.

y = 4

Simplifying

y = 4

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3 years ago
The function V(t)=1,000(1.06)^t models the value of an investment after t years. What does the ".06" represent in the function?
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Step-by-step explanation:

Looking at the function, we have;

V(t) = 1,000(1.06)^t

Mathematically, the amount earned on an investment that offers a particular constant percentage return to a particular number of years can be written as;

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Let’s now re-write what we can deduce in the question.

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8 0
3 years ago
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Step-by-step explanation:

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You are at a stall at a fair where you have to throw a ball at a target. There are two versions of the game. In the first
Tomtit [17]

Answer:

P(X=0)=(3C0)(0.1)^0 (1-0.1)^{3-0}=0.729

And the probability of loss with the first wersion is 0.729

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And the probability of loss with the first wersion is 0.774

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Step-by-step explanation:

Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

Solution to the problem

Alternative 1

Let X the random variable of interest, on this case we now that:

X \sim Binom(n=3, p=0.1)

The probability mass function for the Binomial distribution is given as:

P(X)=(nCx)(p)^x (1-p)^{n-x}

Where (nCx) means combinatory and it's given by this formula:

nCx=\frac{n!}{(n-x)! x!}

We can find the probability of loss like this P(X=0) and if we find this probability we got this:

P(X=0)=(3C0)(0.1)^0 (1-0.1)^{3-0}=0.729

And the probability of loss with the first wersion is 0.729

Alternative 2

Let Y the random variable of interest, on this case we now that:

Y \sim Binom(n=5, p=0.05)

The probability mass function for the Binomial distribution is given as:

P(Y)=(nCy)(p)^y (1-p)^{n-y}

Where (nCx) means combinatory and it's given by this formula:

nCy=\frac{n!}{(n-y)! y!}

We can find the probability of loss like this P(Y=0) and if we find this probability we got this:

P(Y=0)=(5C0)(0.05)^0 (1-0.05)^{5-0}=0.774

And the probability of loss with the first wersion is 0.774

As we can see the best alternative is the first version since the probability of loss is lower than the probability of loss on version 2.

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How you divide a decimal
Tom [10]
Easy you just divide it like a regular then put move the decimal to the left the number of times letters are behind it.
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3 years ago
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