Given:

To find:
The
.
Solution:
In circle B,
is central angle and
is inscribed angle from two points A and C.
According to central angle theorem, central angle is always twice of inscribed angle.
[Central angle theorem]

Divide both sides by 2.


Therefore,
.
Answer:
There is a 0.82% probability that a line width is greater than 0.62 micrometer.
Step-by-step explanation:
Problems of normally distributed samples can be solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by

After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X. The sum of the probabilities is decimal 1. So 1-pvalue is the probability that the value of the measure is larger than X.
In this problem
The line width used for semiconductor manufacturing is assumed to be normally distributed with a mean of 0.5 micrometer and a standard deviation of 0.05 micrometer, so
.
What is the probability that a line width is greater than 0.62 micrometer?
That is 
So



Z = 2.4 has a pvalue of 0.99180.
This means that P(X \leq 0.62) = 0.99180.
We also have that


There is a 0.82% probability that a line width is greater than 0.62 micrometer.
Answer:
1 x (4 x 2) = 8
Step-by-step explanation:
1 x (4 x 2) = 8
Which ever on is on the whole side of the side of the decimal...or in other words, what ever number is on the left side of the decimal
Answer: 6x - 4
Step-by-step explanation: -2*f(x) = -2 * (-3x+2) = (-2*-3x) + (-2*2) = 6x + (-4) = 6x - 4