All categories

3 years ago

What is 15% of 60? Create a model to prove your answer

Mathematics

2 answers:

jolli1 [7]3 years ago

4 0

Answer:

Step-by-step explanation:

xeze [42]3 years ago

3 0

Answer:

25%

Step-by-step:

Convert fraction (ratio) 15 / 60 Answer: 25%

You might be interested in

A bat and a ball cost one dollar and ten cents in total. The bat costs a dollar more than the ball. How much does the ball cost?

lozanna [386]

10 cents becuase you just - it

5 0

3 years ago

Read 2 more answers

"If A, then B" is the form of a statement.

Allisa [31]

Answer:

Hello!

__________________

"If A, then B" is the form of a statement then it is conditional statement.

Hope this helped you!

:D

3 0

3 years ago

Jane is planting a mixture of flowers. For every ounce of Marigold seeds she uses 2/5 of an ounce of lupine seeds how many ounce

dusya [7]

Answer:

$\frac{5}{2}$ ounces of marigold seeds.

Step-by-step explanation:

We have been given that Jane uses 2/5 of an ounce of lupine seeds for every ounce of Marigold seeds. We are asked to find the ounces of Marigold seeds, which Jane will use, if she used one ounce of lupine seeds.

We will use proportions to solve our given problem.

$\frac{\text{Marigold seeds}}{\text{Lupine seeds}}=\frac{1}{\frac{2}{5}}$

Let us simplify our proportion as shown below:

$\frac{\text{Marigold seeds}}{\text{Lupine seeds}}=\frac{1\cdot 5}{2}$

$\frac{\text{Marigold seeds}}{\text{Lupine seeds}}=\frac{5}{2}$

Since Jane used 1 pounce of lupine seeds, so we will substitute this value in our proportion as:

$\frac{\text{Marigold seeds}}{1}=\frac{5}{2}$

$\text{Marigold seeds}}=\frac{5}{2}$

Therefore, Jane will use $\frac{5}{2}$ ounces of marigold seeds, if she used one ounce of lupine seeds.

6 0

3 years ago

Please help! I don't understand how to solve this problem

Ilia_Sergeevich [38]

Using the z-distribution, a sample of 142,282 should be taken, which is not practical as it is too large of a sample.

<h3>What is a z-distribution confidence interval?</h3>

The confidence interval is:

$\overline{x} \pm z\frac{\sigma}{\sqrt{n}}$

The margin of error is:

$M = z\frac{\sigma}{\sqrt{n}}$

In which:

$\overline{x}$ is the sample mean.

z is the critical value.

n is the sample size.

$\sigma$ is the standard deviation for the population.

Assuming an uniform distribution, the standard deviation is given by:

$S = \sqrt{\frac{(4 - 0)^2}{12}} = 1.1547$

In this problem, we have a 95% confidence level, hence $\alpha = 0.95$ , z is the value of Z that has a p-value of $\frac{1+0.95}{2} = 0.975$ , so the critical value is z = 1.96.