Answer:
The answer is "The null hypothesis was rejected".
Step-by-step explanation:
Following are the right-tailed test:
Calculating the null and alternative hypothesis:

![= \frac{0.4267 - 0.3333}{[\sqrt{\frac{(0.3333 \times 0.6667)}{150}}]}\\\\= 2.426](https://tex.z-dn.net/?f=%3D%20%5Cfrac%7B0.4267%20-%200.3333%7D%7B%5B%5Csqrt%7B%5Cfrac%7B%280.3333%20%5Ctimes%200.6667%29%7D%7B150%7D%7D%5D%7D%5C%5C%5C%5C%3D%202.426)
Calculating the right-tailed test:

Therefore, we reject the null hypothesis.
This example shows that more than a third of the families own pets in this town.
In order to calculate the amount, we simply substitute the number of years into x in both equations.
After 3 years:
f(3) = 5(3) + 150
= $165
g(3) = 150 * 1.03⁽³⁾
= $163.90
After 10 years:
f(10) = 5(10) + 150
= $200
g(10) = 150 * 1.03⁽¹⁰⁾
= $201.59
After three years, the first account has more money but after ten years, the second account has more money.
Answer:

Step-by-step explanation:

Answer:
k = 3.9
Step-by-step explanation:
Since the three possible outcomes are given. Therefore, the sum of all the probabilities of the three possible outcomes will be equal to one:

<u>k = 3.9</u>