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Masteriza [31]
3 years ago
13

PLZ HELP SCALE FACTOR TRIANGLE A. 10.5 cm B. 31.5 cm C. 63 cm D. 189 cm

Mathematics
1 answer:
Anarel [89]3 years ago
3 0

If two similar triangles have sides in the ratio a : b, then their areas are in the ratio a² : b².

We have the ratio:

54:18=\dfrac{54}{18}=3:1

Area of the smaler triangle = x

Area of the larger triangle = 567 cm²

Therefore we have the equation:

567:x=3^2:1^2\\\\\dfrac{567}{x}=\dfrac{9}{1}\qquad|\text{cross multiply}\\\\9x=567\qquad|\text{divide both sides by 9}\\\\x=63

<h3>Answer: C. 63 cm²</h3>
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given the arithemtic or geometric sequence, identify f(0) and the common difference ratio f(x) = 4-2/3x
ankoles [38]

<u>Answer: </u>

Required value of f(0) = 4 and common difference of given sequence is \frac{-2}{3}

<u>Solution: </u>

Given sequence rule for arithmetic sequence is  \mathrm{f}(\mathrm{x})=4-\left(\frac{2}{3}\right) x

We need to determine f(0) and common difference

Calculating f(0).

Substituting x = 0 in given sequence rule  we get

\begin{array}{l}{f(0)=4-\left(\frac{2}{3}\right) 0} \\ {=4-0=4}\end{array}

Calculating common difference  

Let’s first calculate f(1) and f(2).

Substituting x = 1 in given sequence rule  

\begin{array}{l}{\mathrm{f}(1)=4-\left(\frac{2}{3}\right) 1} \\ {=4-\left(\frac{2}{3}\right)=\frac{10}{3}}\end{array}

\mathrm{f}(2)=4-\left(\frac{2}{3}\right) 2=4-\left(\frac{4}{3}\right)=\frac{8}{3}

Common Difference can be found by subtracting f(1) from f(2)

\text { Common difference }=\mathrm{f}(2)-\mathrm{f}(1)=\left(\frac{8}{3}\right)-\left(\frac{10}{3}\right)=\frac{-2}{3}

Hence required value of f(0) = 4 and common difference of given sequence is \frac{-2}{3}

7 0
2 years ago
The function y = |x + 6| is a transformation of the parent function
charle [14.2K]

Answer:

in the lefthand direction

Step-by-step explanation:

in  |x + 6| , the +6 means that it shifts left by 6 units

if it was -6, it was should right by 6 units

6 0
2 years ago
For a fruit salad recipe, Jenna combined 3/8 cup of raisins, 7/8 cup of oranges and 3/4 cups of apples. How many cups of fruit a
mojhsa [17]
If you would like to know how many cups of fruits are in the salad, you can calculate this using the following steps:

3/8 cup of raisins + 7/8 cup of oranges + 3/4 cup of apples = 3/8 + 7/8 + 3/4 = 10/8 + 3/4 = 5/4 + 3/4 = 8/4 = 2 cups of fruits

The correct result would be 2 cups of fruits.
7 0
3 years ago
If n^3=x and n^4=20x , where n&gt;0, what is the value of x?
Natali5045456 [20]

Step-by-step explanation:

∠2 and ∠7 are alternate exterior angles so they are equal.

So you can create the equation

40x-48 = 20x+52   Subtract 20x from both sides. Add 48 to both sides.

20x = 100

x = 5

if you need  m∠2 Substtute 5 for x in 20x+52  

20(5) + 52 = 100 +52   m∠2= 152°

m∠7  40(5) - 48 =  200-48  m∠7= 152°

6 0
3 years ago
Approximately how many times as great is the volume of a grapefruit with a diameter 16 cm as the volume of a lime with a diamete
SIZIF [17.4K]

Answer: The volume of the grapefruit is approximately 8 times as great as the volume of the lime.

Step-by-step explanation:

You need to use the formula for calculate the volume of a sphere. This is:

V=\frac{4}{3}\pi  r^3

Where "r" is the radius.

<u>Volume of the grapefruit</u>

You know that its diameter is 16 centimeters.

Since the radius is half the diameter, you get that its volume is:

V_g=\frac{4}{3}\pi  (\frac{16\ cm}{2}) ^3\\\\V_g= 2,144.66\ cm^3

<u> Volume of the lime</u>

According to the information given in the exercise, the diameter of the lime is 8 centimeters.

As it was explained above, the radius is half the diameter. Knowing that, you get that volume of the lime is the shown below:

V_l=\frac{4}{3}\pi  (\frac{8\ cm}{2}) ^3\\\\V_l= 268.08\ cm^3

In order to find approximately how many times as great is the volume of theat grapefruit as the volume of that lime, you need to divide the volumes calculated above. Then:

\frac{2,144.66\ cm^3}{268.08\ cm^3}\approx8\ times

8 0
3 years ago
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