<u>Answer:
</u>
Required value of f(0) = 4 and common difference of given sequence is 
<u>Solution:
</u>
Given sequence rule for arithmetic sequence is 
We need to determine f(0) and common difference
Calculating f(0).
Substituting x = 0 in given sequence rule we get

Calculating common difference
Let’s first calculate f(1) and f(2).
Substituting x = 1 in given sequence rule


Common Difference can be found by subtracting f(1) from f(2)

Hence required value of f(0) = 4 and common difference of given sequence is 
Answer:
in the lefthand direction
Step-by-step explanation:
in |x + 6| , the +6 means that it shifts left by 6 units
if it was -6, it was should right by 6 units
If you would like to know how many cups of fruits are in the salad, you can calculate this using the following steps:
3/8 cup of raisins + 7/8 cup of oranges + 3/4 cup of apples = 3/8 + 7/8 + 3/4 = 10/8 + 3/4 = 5/4 + 3/4 = 8/4 = 2 cups of fruits
The correct result would be 2 cups of fruits.
Step-by-step explanation:
∠2 and ∠7 are alternate exterior angles so they are equal.
So you can create the equation
40x-48 = 20x+52 Subtract 20x from both sides. Add 48 to both sides.
20x = 100
x = 5
if you need m∠2 Substtute 5 for x in 20x+52
20(5) + 52 = 100 +52 m∠2= 152°
m∠7 40(5) - 48 = 200-48 m∠7= 152°
Answer: The volume of the grapefruit is approximately 8 times as great as the volume of the lime.
Step-by-step explanation:
You need to use the formula for calculate the volume of a sphere. This is:

Where "r" is the radius.
<u>Volume of the grapefruit</u>
You know that its diameter is 16 centimeters.
Since the radius is half the diameter, you get that its volume is:

<u> Volume of the lime</u>
According to the information given in the exercise, the diameter of the lime is 8 centimeters.
As it was explained above, the radius is half the diameter. Knowing that, you get that volume of the lime is the shown below:

In order to find approximately how many times as great is the volume of theat grapefruit as the volume of that lime, you need to divide the volumes calculated above. Then:
