<h3>Answer: Choice B) 8.57</h3>
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Explanation:
The triangles are similar through the AA (angle angle) similarity rule. Note how the angle markers correspond and match up. Example: angle C and angle F both have triple angle markers to indicate these angles are congruent.
The corresponding sides pair up to form equal fractions. AB and DE form AB/DE which is equal to AC/DF, as these two sides correspond as well.
Therefore: AB/DE = AC/DF
Let's plug in the given values and isolate x
AB/DE = AC/DF
11/7 = (15+x)/15 ...... substitution
11*15 = 7*(15+x) ....... cross multiply
11*15 = 7*15+7*x ...... distribute
165 = 105+7x
165-105 = 105+7x-105 ..... subtract 105 from both sides
60 = 7x
7x = 60
7x/7 = 60/7 ............ divide both sides by 7
x = 8.57142857142858
x = 8.57 ..... rounding to the nearest hundredth
Y=radical 3
just cancel out the 2 on both sides
Answer:
C. $97
Step-by-step explanation:
The average of his wage for all 15 days is the sum of all wages for the 15 days divided by 15.
average wage for 15 days = (sum of wages for the 15 days)/15
The amount of wages during a number of days is the product of the average wage of those days and the number of days.
First 7 days:
average wage: $87
number of days: 7
total wages in first 7 days = 7 * $87/day = $609
Last 7 days:
average wage: $92
number of days: 7
total wages in last 7 days = 7 * $92/day = $644
8th day:
wages of the 8th day is unknown, so we let x = wages of the 8th day
total wages of 15 days = (wages of first 7 days) + (wages of 8th day) + (wages of last 7 days)
total wages of 15 days = 609 + x + 644 = x + 1253
average wage for 15 days = (sum of wages for the 15 days)/15
average wage for 15 days = (x + 1253)/15
We are told the average for the 15 days is $90/day.
(x + 1253)/15 = 90
Multiply both sides by 15.
x + 1253 = 1350
Subtract 1253 from both sides.
x = 97
Answer: $97
Answer:
Step-by-step explanation:
<u>The numbers from 1 to 9999 can be shown in the form of:</u>
Each of x, y, z represent the digits from 0 to 9, so 10 ways each.
<u>For each of the forms we have:</u>
<u>Total of:</u>
By the way this is applicable to any digit.
