All categories

2 years ago

Passes through (2, 3) at a gradient of 2

Mathematics

1 answer:

Tcecarenko [31]2 years ago

6 0

Answer:

y = 2x-1

Step-by-step explanation:

I'm guessing gradient of 2 means slope of 2

if line passes through (2,3) and has a slope of 2, we can use the slope intercept equation

slope-intercept (y=mx+b)

m is the slope and b is the y-intercept (which we are trying to find)

so far, we have a point and a slope so we can fill in x,y, and m

(3) = (2)(2) + b

3 = 4 + b

3-4 = 4-4 + b (to undo addition, you use subtraction so I minus 4 from each side)

-1 = b

we found b so we just take the (2,3) out of the equation substitute the x,y back into the equation

y = 2x - 1

You might be interested in

A person spends 1/5 of his salary on rent, 3/7 on food, 1/3 on other expenses and saves the rest. If she earns $21,000 per month

sukhopar [10]

Answer:

$9600 saving / year

Step-by-step explanation:

1/5 of $21000 = 21000 / 5 = $4200 / month on rent

3/7 of $21000 = (21000 / 7) x 3 = $9000 / month on food (shocking right :) food is expensive)

1/3 of $21000 = 21000 / 3 = $7000 on other expenses / month

total savings/month = salary/month - rent/month - food/month - other expenses/month

total savings/month = 21000 - 4200 - 9000 - 7000

total savings/month = $800

<u><em>BUT</em></u> the question asks for savings per year. therefore, we must multiply the savings per month by total months per year (12)

800 x 12 = $9600

the person's total savings per year, with a salary of $21000 per month, is equal to $9600 per year

3 0

1 year ago

A parallelogram has an area of 60 square inches. If the base of the parallelogram is 12 inches, what is the height of the parall

Vikentia [17]

How to find the area of a parallelogram is length times height. 12 times what gets you to 60? 5 does. 12 times 5 is 60.

HEIGHT: 5

8 0

3 years ago

Someone please be awesome and help me please :(

solong [7]

Answer:

$(x+\frac{b}{2a})^2+(\frac{4ac}{4a^2}-\frac{b^2}{4a^2})=0$

$(x+\frac{b}{2a})^2=\frac{b^2-4ac}{4a^2}$

$x=\frac{-b}{2a} \pm \frac{\sqrt{b^2-4ac}}{2a}$

Step-by-step explanation:

$x^2+\frac{b}{a}x+\frac{c}{a}=0$

They wanted to complete the square so they took the thing in front of x and divided by 2 then squared. Whatever you add in, you must take out.

$x^2+\frac{b}{a}x+(\frac{b}{2a})^2+\frac{c}{a}-(\frac{b}{2a})^2=0$

Now we are read to write that one part (the first three terms together) as a square:

$(x+\frac{b}{2a})^2+\frac{c}{a}-(\frac{b}{2a})^2=0$

I don't see this but what happens if we find a common denominator for those 2 terms after the square. (b/2a)^2=b^2/4a^2 so we need to multiply that one fraction by 4a/4a.

$(x+\frac{b}{2a})^2+\frac{4ac}{4a^2}-\frac{b^2}{4a^2}=0$

They put it in ( )

$(x+\frac{b}{2a})^2+(\frac{4ac}{4a^2}-\frac{b^2}{4a^2})=0$

I'm going to go ahead and combine those fractions now:

$(x+\frac{b}{2a})^2+(\frac{-b^2+4ac}{4a^2})=0$

I'm going to factor out a -1 in the second term ( the one in the second ( ) ):

$(x+\frac{b}{2a})^2-(\frac{b^2-4ac}{4a^2})=0$

Now I'm going to add (b^2-4ac)/(4a^2) on both sides:

$(x+\frac{b}{2a})^2=\frac{b^2-4ac}{4a^2}$

I'm going to square root both sides to rid of the square on the x+b/(2a) part:

$x+\frac{b}{2a}=\pm \sqrt{\frac{b^2-4ac}{4a^2}}$

$x+\frac{b}{2a}=\pm \frac{\sqrt{b^2-4ac}}{2a}$

Now subtract b/(2a) on both sides:

$x=\frac{-b}{2a} \pm \frac{\sqrt{b^2-4ac}}{2a}$

Combine the fractions (they have the same denominator):

$x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}$

6 0

3 years ago

Which equation represents a line which is perpendicular to the x-axis?

nikklg [1K]

Y= 4 is perpendicular to the x- axis

The x- axis is the horizontal line, and the y- axis is the vertical line

6 0

2 years ago

Anand needs to hire a plumber. He's considering a plumber that charges an initial fee of $ 65 $65dollar sign, 65 along with an h

user100 [1]

Answer:

Step-by-step explanation:

Basic Charge = $ 65

Rate per hour = $ 28

Number of hours = H

Rate for H hours = 28 *H = 28H

Equation:

65 + 28H ≤ 250

7 0

3 years ago

Read 2 more answers