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vaieri [72.5K]
3 years ago
13

Tim had 1/4 of a large pizza. he gave it to his freinds to share equally. what amount of pizza did each friend get?​

Mathematics
1 answer:
IrinaK [193]3 years ago
7 0

Considering his friends were no more then teo, who's name was Robert, thrn you know the answer

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The maximum value of 12 sin 0-9 sin²0 is: -​
jeka57 [31]

Answer:

4

Step-by-step explanation:

The question is not clear. You have indicated the original function as 12sin(0) - 9sin²(0)

If so, the solution is trivial. At 0, sin(0) is 0 so the solution is 0

However, I will assume you meant the angle to be \theta rather than 0 which makes sense and proceed accordingly

We can find the maximum or minimum of any function by finding the first derivate and setting it equal to 0

The original function is

f(\theta) = 12sin(\theta) - 9 sin^2(\theta)

Taking the first derivative of this with respect to \theta and setting it equal to 0 lets us solve for the maximum (or minimum) value

The first derivative of f(\theta) w.r.t \theta is

                        12\cos\left(\theta\right)-18\cos\left(\theta\right)\sin\left(\theta\right)

And setting this = 0 gives

12\cos\left(\theta\right)-18\cos\left(\theta\right)\sin\left(\theta\right) = 0

Eliminating cos(\theta) on both sides and solving for sin(\theta) gives us

sin(\theta) = \frac{12}{18} = \frac{2}{3}

Plugging this value of sin(\theta) into the original equation gives us

12(\frac{2}{3}) - 9(\frac{4}{9} ) = 8 - 4 = 4

This is the maximum value that the function can acquire. The attached graph shows this as correct

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A rectangular pool has a length of
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Rewrite the function W= 50+2.3(h-60) in order to express height as a function of weight
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You need to solve the equation for h.

<span>W= 50+2.3(h-60)

Distribute the 2.3.

W = 50 + 2.3h - 138

W = 2.3h - 88

Add 88 to both sides.

W + 88 = 2.3h

Switch sides.

2.3h = W + 88

Divide both sides by 2.3.

h = (W + 88)/2.3
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LKM≈TEJ since it makes the triangles congruent, although the angles in each triangle are not corresponding equal angles
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