st + 3t = 6 for s
Subtract 3t to both sides
st + 3t - 3t = 6 - 3t
Simplify
st = 6 - 3t
Divide both sides by t
st/t = (6-3t)/3
simplify
s = 6/3 - 3t/3
s = 2 - t
the constant term is 12
All the other terms have variables attached to them
Answer:
angazii ukuthii ngingaku siza kanjanii lahh
a) Altitude of triangle ABC
b) Angle bisector of angle H
c) Median of triangle JKL
Answer:
15 hours
Step-by-step explanation:
Given:
Fernell's speed
mph
Dabney's speed
mph
Denote:
- distance covered by Fernell
- distance covered by Dabney
- Fernell's time
- Dabney's time
1. If Fernell drove for 3 hours longer than Dabney, then his time is 3 hours more than Dabney's time and

2. If Fernell covered 18 miles less than Dabney, then

Use formula 

Subtract from the first equation the second equation and equate it to 18:

