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3 years ago

Please help I’m so confused Please don’t use the link joke

Mathematics

1 answer:

jarptica [38.1K]3 years ago

7 0

Answer:

i think it's 2.2

Step-by-step explanation:

it looks like (5,11) is a point that the line crosses so when you divide 11 by 5, would get 2.2

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I have a cage with cats and birds. there are 12 heads and 32 feet. how many birds are there

Sati [7]

12x4=48

48-32=16

4-2=2

16 divided by 2=8 birds

5 0

3 years ago

Read 2 more answers

Factor the expression x2 - 49. A. 7(x² – 7) B. 7.(2-7) C. 2+7(2-7) D. (x + 7)(x-7)

NISA [10]

X^2 - 49 = (x + 7)(x - 7) = x^2 - 7x + 7x = 49 = x^2 - 49

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3 years ago

What is the domain and range of y=-1/4(x)

LenKa [72]

Domain: $(-\infty, \infty)$

Range: $(-\infty, \infty)$

Explanation:

The function is $y=-\frac{1}{4} x$

The domain of a function is the set of all input values for which the function is well defined. Generally, domain consists of all x-values of the function. Hence, the function $y=-\frac{1}{4} x$ is defined in the interval $(-\infty, \infty)$ .

The range of a function is the set of output values obtained by substituting the value of x in the function. Hence, the function $y=-\frac{1}{4} x$ is defined in the interval $(-\infty, \infty)$ .

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3 years ago

A bottle of perfume holds 0.55 onice. A bottle of cologne holds p.2 ounce. How many more ounces dose the bottle of perfume hold?

zimovet [89]

It has .33 more ounces if that says .2

7 0

3 years ago

. The mean width of 12 iPads is 5.1 inches. The mean width of 8 Kindles is 4.8 inches. a. What is the total width of the iPads?

UkoKoshka [18]

Answer:

a) 61.2, b) 38.4 and c) 4.98

Step-by-step explanation:

Given:

The mean width of 12 I-Pads is 5.1 inches.

The mean width of 8 Kindles is 4.8 inches.

Question asked:

a. What is the total width of the I-Pads?

b. What is the total width of the Kindles?

c. What is the mean width of the 12 I-Pads and 8 Kindles?

Solution:

As we know:

$Mean =\frac{Sum\ of\ observations}{Number\ of\ observations}\\ \\ Mean\ width =\frac{Sum\ of\ width\ of\ all \ I-pad}{Number \ of\ I-pad}$

$5.1=\frac{Sum\ of\ width\ of\ all\ I-pad}{12} \\ \\ By \ cross\ multiplication\\ \\ Sum\ of\ width\ of\ all\ I-pad}=5.1\times1 2\\ \\ Sum\ of\ width\ of\ all\ I-pad}= 61.2$

a) Thus, the total width of the I-Pads are 61.2 inches.

$Mean\ width =\frac{Sum\ of\ width\ of\ all\ Kindles}{Number \ of\ Kindles}$

$4.8=\frac{Sum\ of\ width\ of\ all\Kindles}{8} \\ \\ By \ cross\ multiplication\\ \\ Sum\ of\ width\ of\ all \ Kindles=4.8\times8\\ \\ Sum\ of\ width\ of \ all\ Kindles}=38.4$

b) Thus, total width of the Kindles are 38.4 inches.

Combined width of both I-pad and Kindles = 61.2 + 38.4 = 99.6 inches

Combined number of observations = 12 + 8 =20

Combined mean of width of the 12 I-Pads and 8 Kindles = Combined width of both I-pad and Kindles $\div$ Combined number of observations

Combined mean of width of the 12 I-Pads and 8 Kindles = $\frac{99.6}{20} =4.98\ inches$

c) Thus, the mean width of the 12 I-Pads and 8 Kindles is 4.98 inches.

5 0

3 years ago