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slava [35]
4 years ago
12

A fruit salad is made from pineapples, pears, and peaches mixed in the ratio of 2 to 3 to 5, respectively, by weight. What fract

ion of the mixture by weight is pineapple?
Can you explain this so I can understand how it works?
Mathematics
1 answer:
solniwko [45]4 years ago
4 0
2/10, is it that because you need to find how much fruit in total to calculate for the fraction, so 2+3+5= 10 so 10 will be you're bottom number. Then you need to look at how many pineapple there are to then make the fraction 2/10 because there are 2 pineapples out of the 10 fruits. Hope that helps!!
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Evaluate the expression 2(8-4)² - 10 ÷ 2
expeople1 [14]
The answer is 27 hope it helps
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4/7 times 3/9 answer
bagirrra123 [75]
4\7 x 3\9 = 12\63
4 x 3 = 12
7 x 9 = 63
Hope this helps!
3 0
3 years ago
-5 (1-5x)+5 (-8x-2)=-4x-8x ahhh plz send help
Yanka [14]

2x√8-x - x/2√8-x is the answer

7 0
4 years ago
What is the definite integral of log (tan x) with range from 90 to 0
nasty-shy [4]

Substituting <em>x</em> with <em>π</em>/2 - <em>x</em> gives the equivalent integral,

\displaystyle\int_0^{\frac\pi2}\log(\tan(x))\,\mathrm dx=-\int_{\frac\pi2}^0\log(\cot(x))(-\mathrm dx)=\int_0^{\frac\pi2}\log(\cot(x))\,\mathrm dx

So if we let <em>J</em> denote the value of the integral, we have

J=\displaystyle\int_0^{\frac\pi2}\log(\tan (x))\,\mathrm dx

J=\displaystyle\int_0^{\frac\pi2}\log(\cot (x))\,\mathrm dx

\implies 2J=\displaystyle\int_0^{\frac\pi2}\left(\log(\tan (x))+\log(\cot (x))\right)\,\mathrm dx

Condensing the logarithms, we have

log(tan(<em>x</em>)) + log(cot(<em>x</em>)) = log(tan(<em>x</em>) cot(<em>x</em>)) = log(1) = 0

since cot(<em>x</em>) = 1/tan(<em>x</em>), which means

2J=\displaystyle\int_0^{\frac\pi2}0\,\mathrm dx=0

and so the original integral has a value of <em>J</em> = 0.

3 0
3 years ago
Solve the equation after making an appropriate substitution. X^6-98x^3=3375
Leni [432]
Rearrange x^6-98x^3=3375 to give

x^6-98x^3-3375=0

Let x^3 be a variable 'p' and so we can write x^6 as x^6=(x^3)(x^3)=(p)(p)= p^2

Rewrite the equation in terms of 'p'

p^2-98p-3375 = 0

where a=1, b=-98, c=-3375

using the quadratic formula \frac{-b+ \sqrt{b^2-4ac} }{2a} and subsitute the value of a, b, c

p_1= \frac{-(-98)+ \sqrt{(-98)^2-4(1)(-3375)} }{2} =125

p_2= \frac{-(-98)- \sqrt{(-98)^2-4(1)(-3375)} }{2} =-27

There are two value of p; 125 and -27 

Now we find the value of x

Earlier we substitute x^3 for p and x^6 for p^2

When p=125, x= \sqrt[3]{125}=5
When p = -27, x= \sqrt[3]{-27}=-3

So the final answer is the two values of x; 

x = 5 OR x = -3
3 0
3 years ago
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