Compute the missing data in the table for the following exponential function

Mathematics

2 answers:

babunello [35]3 years ago

4 0

Answer:

The correct option is:

d. 1

Step-by-step explanation:

x : 0 1 2 3 4 5 6

f(x): ? 1.01 1.02 1.03 1.04 1.05 1.06

Clearly, we can see that the f(x) is increasing as the x is increasing and uniformly

at 1 its value is 1.01

at 2 its value is 1.02

at 3 its value is 1.03 and so on

Hence, at 0 its value will be 1.00

Hence, the correct option is:

d. 1

kramer3 years ago

3 0

Answer:

d. 1

Step-by-step explanation:

The base for this "exponential" function is sufficiently close to 1 that the function looks linear. The value corresponding to x=0 seems to be 1.00. Rounded to tenths, it is 1.0.

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Solve -6 4/9-3 2/9-82/9

Gala2k [10]

Answer: The final answer in proper fraction is 169/9

Step-by-step explanation:

Given the expression

-6 4/9-3 2/9-82/9

Firstly let us convert all mixed fraction to proper fraction to further simplify the expression

-58/9 - 29/9 - 82/9

We now have all terms in proper fraction, we can continue by finding the LCM which is 9

= (- 58-29-82)/9

= 169/9

8 0

3 years ago

Answer the question with explanation;

PSYCHO15rus [73]

Answer:

The statement in the question is wrong. The series actually diverges.

Step-by-step explanation:

We compute

$\lim_{n\to\infty}\frac{n^2}{(n+1)^2}=\lim_{n\to\infty}\left(\frac{n^2}{n^2+2n+1}\cdot\frac{1/n^2}{1/n^2}\right)=\lim_{n\to\infty}\frac1{1+2/n+1/n^2}=\frac1{1+0+0}=1\ne0$

Therefore, by the series divergence test, the series $\sum_{n=1}^\infty\frac{n^2}{(n+1)^2}$ diverges.

EDIT: To VectorFundament120, if $(x_n)_{n\in\mathbb N}$ is a sequence, both $\lim x_n$ and $\lim_{n\to\infty}x_n$ are common notation for its limit. The former is not wrong but I have switched to the latter if that helps.