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Fantom [35]
3 years ago
6

Compute the missing data in the table for the following exponential function

Mathematics
2 answers:
babunello [35]3 years ago
4 0

Answer:

The correct option is:

d. 1

Step-by-step explanation:

x :   0  1        2      3       4       5      6  

f(x): ?  1.01  1.02  1.03  1.04  1.05  1.06

Clearly, we can see that the f(x) is increasing as the x is increasing and uniformly

at 1 its value is 1.01

at 2 its value is 1.02

at 3 its value is 1.03 and so on

Hence, at 0 its value will be 1.00

Hence, the correct option is:

d. 1

kramer3 years ago
3 0

Answer:

d. 1

Step-by-step explanation:

The base for this "exponential" function is sufficiently close to 1 that the function looks linear. The value corresponding to x=0 seems to be 1.00. Rounded to tenths, it is 1.0.

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A heavy rope, 50 ft long, weighs 0.6 lb/ft and hangs over the edge of a building 120 ft high. Approximate the required work by a
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Answer:

Exercise (a)

The work done in pulling the rope to the top of the building is 750 lb·ft

Exercise (b)

The work done in pulling half the rope to the top of the building is 562.5 lb·ft

Step-by-step explanation:

Exercise (a)

The given parameters of the rope are;

The length of the rope = 50 ft.

The weight of the rope = 0.6 lb/ft.

The height of the building = 120 ft.

We have;

The work done in pulling a piece of the upper portion, ΔW₁ is given as follows;

ΔW₁ = 0.6Δx·x

The work done for the second half, ΔW₂, is given as follows;

ΔW₂ = 0.6Δx·x + 25×0.6 × 25 =  0.6Δx·x + 375

The total work done, W = W₁ + W₂ = 0.6Δx·x + 0.6Δx·x + 375

∴ We have;

W = 2 \times \int\limits^{25}_0 {0.6 \cdot x} \, dx + 375= 2 \times \left[0.6 \cdot \dfrac{x^2}{2} \right]^{25}_0 + 375 = 750

The work done in pulling the rope to the top of the building, W = 750 lb·ft

Exercise (b)

The work done in pulling half the rope is given by W₂ as follows;

W_2 =  \int\limits^{25}_0 {0.6 \cdot x} \, dx + 375= \left[0.6 \cdot \dfrac{x^2}{2} \right]^{25}_0 + 375 = 562.5

The work done in pulling half the rope, W₂ = 562.5 lb·ft

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Answer:

3x+ 5 1/3

Step-by-step explanation:

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A square region with perimeter 60 inches is made with square inch tiles. Bob removes one tile from the square and rearranges the
icang [17]

Answer:

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Step-by-step explanation:

The perimeter will be minimized when the tiles are rearranged to form a rectangle with dimensions as close to each other as possible.

<h3>Rectangle dimensions</h3>

The square has a side length of ...

  P = 4s   ⇒   s = P/4 . . . . . P is perimeter, s is side length

  (60 in)/4 = 15 in . . . . length of the side of the square

The square has an area of ...

  A = s²

  A = (15 in)² = 225 in²

When 1 tile is removed, the resulting area, in square inches, is ...

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<h3>Perimeter</h3>

The perimeter of a rectangle is given by ...

  P = 2(L+W)

For this rectangle, the perimeter is ...

  P = 2(14 in + 16 in) = 2(30 in) = 60 in

The perimeter of the rectangle is 60 inches.

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2 years ago
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