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nlexa [21]
4 years ago
7

Convert to milliliters: 34 liters

Mathematics
2 answers:
Alex73 [517]4 years ago
8 0
The answer is

D. 34,000 milliliters
leva [86]4 years ago
5 0

Answer:

D, 34,000 milliliters

Step-by-step explanation:

There are 1,000 milliliters in a liter. So, if we had 1 liter, we would have 1*1,000=1,000 milliliters.

When you change the 1 liter to 34, we can just substitute 34 for 1. So, the answer is 34*1,000=34,000 milliliters, or D

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Artist 52 [7]

cuál de los siguientes documentos es más Útil para construir carretera

3 0
3 years ago
Help with #15 please
jonny [76]

Answer:

3 gallons of carpet shampoo

Step-by-step explanation:

room area: 16 * 15 = 240 ft

1 gallon carpet shampoo: 80 ft

240/80 = 3

3 gallons of carpet shampoo are needed.

6 0
3 years ago
What word best fits this definition
postnew [5]

Answer:

EXTRAPOLATION.

Step-by-step explanation:

We have been given  a crossword puzzle in the figure

And we need to fill the missing word in this which has to be a mathematics word because we need to follow the pattern

And all words are mathematical

Hence, The word that can be filled there is EXTRAPOLATION.

Extrapolation means in mathematics is finding value of the variable on basis of the relationship this variable have with other variable.

6 0
3 years ago
A man walked 6 km per hour how far does he work between 9:30 a.m. and 12 p.m.​
kolbaska11 [484]

Answer:

15 km

Step-by-step explanation:

9:30 to 12:00 = 2.5 hours

2.5 x 6 = 15

8 0
3 years ago
Read 2 more answers
An adult brain is about 140 mm wide and divided into two sections (called "hemispheres" although the brain is not truly spherica
Sedbober [7]

Answer: 3.61×10^5 A

Step-by-step explanation: Since the brain has been modeled as a current carrying loop, we use the formulae for the magnetic field on a current carrying loop to get the current on the hemisphere of the brain.

The formulae is given below as

B = u×Ia²/2(x²+a²)^3/2

Where B = strength of magnetic field on the axis of a circular loop = 4.15T

u = permeability of free space = 1.256×10^-6 mkg/s²A²

I = current on loop =?

a = radius of loop.

Radius of loop is gotten as shown... Radius = diameter /2, but diameter = 65mm hence radius = 32.5mm = 32.5×10^-3 m = 3.25×10^-2m

x = distance of the sensor away from center of loop = 2.10 cm = 0.021m

By substituting the parameters into the formulae, we have that

4.15 = 1.256×10^-6 × I × (3.25×10^-2)²/2{(0.021²) + (3.25×10^-2)²}^3/2

4.15 = 13.2665 × 10^-10 × I/ 2( 0.00149725)^3/2

4.15 = 1.32665 ×10^-9 × I / 2( 0.000058)

4.15 × 2( 0.000058) = 1.32665 ×10^-9 × I

I = 4.15 × 2( 0.000058)/ 1.32665 ×10^-9

I = 4.80×10^-4 / 1.32665 ×10^-9

I = 3.61×10^5 A

3 0
3 years ago
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