Answer: x = 9.0
Step-by-step explanation:
From the given right angle triangle,
the hypotenuse of the right angle triangle is x
With m∠39 as the reference angle,
the adjacent side of the right angle triangle is 7
The unknown side represents the opposite side of the right angle triangle.
To determine x, we would apply
the cosine trigonometric ratio which is expressed as
Cos θ = adjacent side/hypotenuse. Therefore,
Cos 39 = 7/x
x = 7/cos 39 = 7/0.777
x = 9.0 to the nearest tenth
Answer:
d. (x+2)/(-x²-5)
Step-by-step explanation
ƒ(x) = x + 2/(2x²)
The function is undefined when x = 0.
b. ƒ(x) = (2x + 4)/(3x + 3)
The function is undefined when 3x + 3 = 0, i.e., when x = -1.
c. ƒ(x) = (6x - 5)/(x² - 7)
The function is undefined when x² - 7 = 0, i.e., when x = √7.
d. ƒ(x) = (x+2)/(-x²-5) = -(x+2)/(x² + 5)
The function would be undefined if x² + 5 = 0, i.e., if x² = -5. However, the square of a real number cannot be negative.
This function has no excluded values.
The table shows a linear function. x -5,-4,-3,-2,-1, 0, 1, 2, 3. on top row f(x) -11, -3, 5, 13, 21, 29, 37, 45, 53. on bottom r
NARA [144]
Wouldn’t the inputs be 4 and 5? I could wrong though
The correct question is: evaluate
![\sqrt[3]{- \frac{8}{125} }](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B-%20%5Cfrac%7B8%7D%7B125%7D%20%7D%20)
The
answer is: option B. -2 / 5Explanation:![\sqrt[3]{- \frac{8}{125} }=- \frac{ \sqrt[3]{8} }{ \sqrt[3]{125} } =- \frac{ \sqrt[3]{2^3} }{ \sqrt[3]{5^3} } =- \frac{2}{5}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B-%20%5Cfrac%7B8%7D%7B125%7D%20%7D%3D-%20%5Cfrac%7B%20%5Csqrt%5B3%5D%7B8%7D%20%7D%7B%20%5Csqrt%5B3%5D%7B125%7D%20%7D%20%3D-%20%5Cfrac%7B%20%5Csqrt%5B3%5D%7B2%5E3%7D%20%7D%7B%20%5Csqrt%5B3%5D%7B5%5E3%7D%20%7D%20%3D-%20%5Cfrac%7B2%7D%7B5%7D%20)
