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goldenfox [79]
3 years ago
7

Al's Produce Stand sells 8 ears of corn for $2.25. Barbara's Produce Stand sells 12 ears of corn for $3.50. Write two equations,

one for each produce stand, that model the relationship between the number of ears of corn sold and the cost. Then, use each equation to help complete the tables below. ​
Mathematics
1 answer:
Gennadij [26K]3 years ago
3 0

Answer:

6n = 1.50

and

13n = 3.12

Step-by-step explanation:

Here in this question, we are interested in writing equations that relate the number of ears of corn sold and the cost.For Al’s produce stand, let the price per corn sold be n

Thus;

6 * n = 1.50

6n = $1.50 •••••••(i)

For the second;

let the price per corn sold be n;

13 * n = $3.12

-> 13n = 3.12 •••••••••(ii)

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Solve this question please
mr_godi [17]

Answer:

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Step-by-step explanation:

if its not right than sorry

4 0
3 years ago
If F(x) = f(x)g(x), where f and g have derivatives of all orders
user100 [1]

a. By the product rule,

F=fg\implies F'=f'g+fg'

\implies F''=(f''g+f'g')+(f'g'+fg'')=f''g+2f'g'+fg''

b. By the same rule,

F'''=(f'''g+f''g')+2(f''g'+f'g'')+(f'g''+fg''')

F'''=f'''g+3f''g'+3f'g''+fg'''

and

F^{(4)}=(f^{(4)}g+f'''g')+3(f'''g'+f''g'')+3(f''g''+f'g''')+(f'g'''+fg^{(4)})

F^{(4)}=f^{(4)}g+4f'''g'+6f''g''+4f'g'''+fg^{(4)}

c. You might recognize the coefficients as those that appear in the expansion of (a+b)^n:

1, 1

1, 2, 1

1, 3, 3, 1

1, 4, 6, 4, 1

and so on; the general pattern (known as the general Leibniz rule) is

F^{(n)}=\displaystyle\sum_{k=0}^n\binom nkf^{(n-k)}g^{(k)}

6 0
3 years ago
Find the coordinates of point G
LiRa [457]

Answer:

  G = (2, 9)

Step-by-step explanation:

The midpoint is the average of the endpoints, so we have ...

  M = (G+H)/2

Solving for G gives ...

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3 0
3 years ago
The rate of change (dP/dt), of the number of people on an ocean beach is modeled by a logistic differential equation. The maximu
Kazeer [188]

Answer:

\frac{dP}{dt} = 2.4P(1 - \frac{P}{1200})

Step-by-step explanation:

The logistic differential equation is as follows:

\frac{dP}{dt} = rP(1 - \frac{P}{K})

In this problem, we have that:

K = 1200, which is the carring capacity of the population, that is, the maximum number of people allowed on the beach.

At 10 A.M., the number of people on the beach is 200 and is increasing at the rate of 400 per hour.

This means that \frac{dP}{dt} = 400 when P = 200. With this, we can find r, that is, the growth rate,

So

\frac{dP}{dt} = rP(1 - \frac{P}{K})

400 = 200r(1 - \frac{200}{1200})

166.67r = 400

r = 2.4

So the differential equation is:

\frac{dP}{dt} = rP(1 - \frac{P}{K})

\frac{dP}{dt} = 2.4P(1 - \frac{P}{1200})

3 0
3 years ago
a rocket is scheduled to launch from a command center in 3.75 hours. what time is it now if launch time is 11:20am. i need to kn
gtnhenbr [62]

The equation would be 3.75+t=11.2 so:

3.75+t=11.2

3.75+t-3.75=11.2-3.75

t=7.45, which is 7:35.


5 0
3 years ago
Read 2 more answers
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