Answer:
Two possible lengths for the legs A and B are:
B = 1cm
A = 14.97cm
Or:
B = 9cm
A = 12cm
Step-by-step explanation:
For a triangle rectangle, Pythagorean's theorem says that the sum of the squares of the cathetus is equal to the hypotenuse squared.
Then if the two legs of the triangle are A and B, and the hypotenuse is H, we have:
A^2 + B^2 = H^2
If we know that H = 15cm, then:
A^2 + B^2 = (15cm)^2
Now, let's isolate one of the legs:
A = √( (15cm)^2 - B^2)
Now we can just input different values of B there, and then solve the value for the other leg.
Then if we have:
B = 1cm
A = √( (15cm)^2 - (1cm)^2) = 14.97
Then we could have:
B = 1cm
A = 14.97cm
Now let's try with another value of B:
if B = 9cm, then:
A = √( (15cm)^2 - (9cm)^2) = 12 cm
Then we could have:
B = 9cm
A = 12cm
So we just found two possible lengths for the two legs of the triangle.
Estimation is a important skill to know when adding and subtracting decimals because if you estimate you have an idea on what your answer should be close to.
For example 4.68-2.38 could be 5-2 which is 3. 4.68-2.38 equals 2.3. 2.3 is close to 3.
To prove that triangles TRS and SUT are congruent we can follow these statements:
1.- SR is perpendicular to RT: Given
2.-TU is perpendicular to US: Given
3.-Angle STR is congruent with angle TSU: Given.
4.-Reflexive property over ST: ST is congruent with itself (ST = ST)
From here, we can see that both triangles TRS and SUT have one angle of 90 degrees, another angle that they both have, and also they share one side (ST) ,then:
5.- By the ASA postulate (angle side angle), triangles TRS and SUT are congruent
Solution
Switch sides so that m is on the left side
m/r = 2r
Them multiply both sides by r
mr/r = 2rr
Now simplify the equation
m = 2r^2
Therefore the equation evaluates to
m = 2r squared by 2
