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3 years ago

Give a real life example of an outlier and explain why is it an outlier.

Mathematics

2 answers:

torisob [31]3 years ago

8 0

Answer:

an example of an outlier is in state testing (which I just did today).

Step-by-step explanation:

say that most of the students got a a score of 78 to 95 the outlier would be something like a score of 30 because it is nowhere near the rest of the numbers and skews the the information when taking the average of a numbers.

Hope this helps! :)

And have a fabulous Friday!!

IrinaVladis [17]3 years ago

3 0

swer:

6,7,8,10,13,15,18,303

303 would be an outlier.

It is an outlier because it has more space between any other number in that list. It is farther apart than any other number the closest number on the list is 18. Which is 285 numbers away! So, an outlier is the odd ones out by distance (hehe you.tube) of a set of data usually numbers.

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What is 1481 rounded to the nearest hundred

laila [671]

Answer:

1500

Step-by-step explanation:

1481 to the nearest hundred is 1500 because 8 is nearer to 10

4 0

3 years ago

Read 2 more answers

Radium-226 is a metal with a half-life of 1600 years. If you start with 1 kilogram of radium-226, how much will remain after 20,

erica [24]

Ending Amount = Beginning Amount / 2^n
where 'n' = # of half lives
n = 20,000 / 1,600 = 12.5 half-lives

Ending Amount = 1 kg / 2^12.5
Ending Amount = 1 kg / 5,792.6
Ending Amount = 0.00017263 kilograms = 0.17263 grams

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4 years ago

Find 3 consecutive even numbers where the product of the smaller two numbers is 40 less than the square of the largest number.

Marina86 [1]

$3\ consecutive\ even\ numbers:\ 2x,2x+2,2x+4\\\\2x(2x+2)+40=(2x+4)^2\\\\
4x^2+4x+40=4x^2+16x+16\\\\
4x^2-4x^2+4x-16x=16-40\\\\-12x=-24\ \ |:(-12)\\\\x=\frac{24}{12}=2\\\\2x=2=4\\\\2x+2=6\\\\2x+4=8\\\\Numbers\ are\ 4,6,8.$

5 0

3 years ago

In a mixture 60 liters, the ratio of milk and water 2:1.If this ratio is to be 1:2, then what is the quantity of water to be fur

ella [17]

Answer:

Hello,

60L

Step-by-step explanation:

Quantity of water /Quantity of milk =2/1

Quantity of mixture= Quantity of water +Quantity of milk =60L

Quantity of milk =40 L

Quantity of water =20 L

Let say x the quantity of water to be added

New ratio =1/2=40/(20+x)

20+x=80 (cross products)

x=60  (L)

4 0

3 years ago

In doing so, you collect a random sample of 50 salespersons employed by his company, which is thought to be representative of sa

Deffense [45]

Answer:

$z=\frac{0.36 -0.45}{\sqrt{\frac{0.45(1-0.45)}{50}}}=-1.279$

$p_v =P(z$

And we can use the following code to find it "=NORM.DIST(-1.279,0,1,TRUE)"

Step-by-step explanation:

Assuming this complete problem: "The CEO of a software company is committed to expanding the proportion of highly qualified women in the organization's staff of salespersons. He believes that the proportion of women in similar sales positions across the country is less than 45%. Hoping to find support for his belief, he directs you to test

H0: p .45 vs H1: p < .45.

In doing so, you collect a random sample of 50 salespersons employed by his company, which is thought to be representative of sales staffs of competing organizations in the industry. The collected random sample of size 50 showed that only 18 were women.

Compute the p-value associated with this test. Place your answer, rounded to 4 decimal places, in the blank. For example, 0.3456 would be a legitimate entry."

1) Data given and notation

n=50 represent the random sample taken

X=18 represent the number of women in the sample selected

$\hat p=\frac{18}{50}=0.36$ estimated proportion of women in the sample

$p_o=0.45$ is the value that we want to test

$\alpha$ represent the significance level

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

2) Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that the proportion of women is less than 0.45:

Null hypothesis: $p\geq 0.45$

Alternative hypothesis: $p < 0.45$

When we conduct a proportion test we need to use the z statistic, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

3) Calculate the statistic

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.36 -0.45}{\sqrt{\frac{0.45(1-0.45)}{50}}}=-1.279$

4) Statistical decision

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The next step would be calculate the p value for this test.

Since is a left tailed test the p value would be:

$p_v =P(z$

And we can use the following code to find it "=NORM.DIST(-1.279,0,1,TRUE)"

4 0

3 years ago