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3 years ago

Give a real life example of an outlier and explain why is it an outlier.

Mathematics

2 answers:

torisob [31]3 years ago

8 0

Answer:

an example of an outlier is in state testing (which I just did today).

Step-by-step explanation:

say that most of the students got a a score of 78 to 95 the outlier would be something like a score of 30 because it is nowhere near the rest of the numbers and skews the the information when taking the average of a numbers.

Hope this helps! :)

And have a fabulous Friday!!

IrinaVladis [17]3 years ago

3 0

swer:

6,7,8,10,13,15,18,303

303 would be an outlier.

It is an outlier because it has more space between any other number in that list. It is farther apart than any other number the closest number on the list is 18. Which is 285 numbers away! So, an outlier is the odd ones out by distance (hehe you.tube) of a set of data usually numbers.

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C an you simplify 5^-8 x 5^4

EastWind [94]

Answer:

1/625

Step-by-step explanation:

Exponent Rule: $(b^m)(b^n) = b^{m+n}$

Exponent Rule: $b^{-m}=\frac{1}{b^m}$

5⁻⁸ · 5⁴ = -8 + 4 = -4

5⁻⁴

1/5⁴

1/625

6 0

3 years ago

Ax+by+c=0 solve for y

kvv77 [185]

$Answer: \large\boxed{y=\frac{-ax}{b} -\frac{c}{b}}$

Step-by-step explanation:

$ax+by+c=0\\ax+by=-c\\by=-ax-c\\y=\frac{-ax-c}{b}\\y=\frac{-ax}{b} -\frac{c}{b}$

8 0

2 years ago

A company wants to establish that the mean life of its batteries, when used in a wireless mouse, is over 183 days. The data will

enyata [817]

Answer:

a) Null and alternative hypotheses are:

$H_{0}$ : mu=183 days

$H_{a}$ : mu>183 days

b) If the true mean is 190 days, Type II error can be made.

Step-by-step explanation:

Let mu be the mean life of the batteries of the company when it is used in a wireless mouse

Null and alternative hypotheses are:

$H_{0}$ : mu=183 days

$H_{a}$ : mu>183 days

Type II error happens if we fail to reject the null hypothesis, when actually the alternative hypothesis is true.

That is if we conclude that mean life of the batteries of the company when it is used in a wireless mouse is at most 183 days, but actually mean life is 190 hours, we make a Type II error.

4 0

3 years ago

Which of the following inequalities matches the graph? graph of an inequality with a dashed line through the points (0, 7) and (

stiks02 [169]

Answer:

2x + y < 7

Step-by-step explanation:

First we find the slope of the line that passes through the given points. The formula for slope is:

$m=\frac{y_2-y_1}{x_2-x_1}$

Using our points, we have

$m=\frac{7-5}{0-1}=\frac{2}{-1}=-2$

The y-intercept will be the point where the data crosses the y-axis. All y-intercepts have an x-coordinate of 0; since we already have the point (0, 7), we have the y-intercept at 7. This makes our equation

y = -2x + 7

The inequalities we're given are written in standard form, Ax+By=C. This means we need x and y on the same side of the equals in our equation.

Since the inequality is graphed below the line, we want our inequality to be

y < -2x+7

To move the x-value to the other side of the equation, we will add 2x to each side:

y+2x < -2x+7+2x

y+2x < 7

2x+y < 7

7 0

3 years ago

Read 2 more answers

The amount of coffee that a filling machine puts into an 8 dash ounce 8-ounce jar is normally distributed with a mean of 8.2 oun

Inessa [10]

Answer:

73.3% probability that the sampling error made in estimating the mean amount of coffee for all 8 dash ounce 8-ounce jars by the mean of a random sample of 100 jars, will be at most 0.02 ounce

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theore.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this question, we have that:

$\mu = 8.2, \sigma = 0.18, n = 100, s = \frac{0.18}{\sqrt{100}} = 0.018$

What is the probability that the sampling error made in estimating the mean amount of coffee for all 8 dash ounce 8-ounce jars by the mean of a random sample of 100 jars, will be at most 0.02 ounce

That is, probability of the sample mean between 8.2-0.02 = 8.18 and 8.2 + 0.02 = 8.22, which is the pvalue of Z when X = 8.22 subtracted by the pvalue of Z when X = 8.18.

X = 8.22

$Z = \frac{X - \mu}{\sigma}$

By the Central Limit Theorem

$Z = \frac{X - \mu}{s}$

$Z = \frac{8.22 - 8.2}{0.018}$

$Z = 1.11$

$Z = 1.11$ has a pvalue of 0.8665.

X = 8.18

$Z = \frac{X - \mu}{s}$

$Z = \frac{8.18 - 8.2}{0.018}$

$Z = -1.11$

$Z = -1.11$ has a pvalue of 0.1335.

0.8665 - 0.1335 = 0.7330

73.3% probability that the sampling error made in estimating the mean amount of coffee for all 8 dash ounce 8-ounce jars by the mean of a random sample of 100 jars, will be at most 0.02 ounce

6 0

3 years ago