Need help with this please and thank you in advance

Mathematics

1 answer:

zhuklara [117]3 years ago

5 0

To solve this question you divide by -1 on both sides to get x by itself. This will get you the answer
$x = 4$

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The students at Midtown Middle school sold flowers as a fundraiser in September and October. In October, they charged $1.50 for

Phoenix [80]

Let the price of flowers in September be x, then (100 + 20)/100 * x = $1.50
120/100 * x = $1.50
1.2x = $1.50
x = $1.50/1.2 = $1.25
The price of flowers in September is $1.25

Total money realised in September = $1.25 x 900 = $1,125
40% earned = 0.4 x $1,125 = $450

Total money realised in October = $1.50 x 700 = $1,050
40% earned = 0.4 x $1,050 = $420

The class earned more money in September and they earned $30 more than in October.

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3 years ago

Michelle bought 4 gallons of grape juice and 5 gallons of apple juice for a party. What is the ratio of gallons of apple juice t

ivann1987 [24]

Answer: 4 to 5

5to 4

Step-by-step explanation:

4 0

2 years ago

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Roy has 5 pounds of dried fruit to make snack bags. He separates each pound of dried fruit into thirds and wants to use 1 third

Dahasolnce [82]

Answer:

Step-by-step explanation:

1 turns in to 3 and you multiply that by 5

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3 years ago

Asap help plz Decrease 1). 400 by 10% 2). 380 by 10% 3). 140 by 15% 4). 35 by 20%.

Varvara68 [4.7K]

1)360 (400*.9)
2)342 (380*.9)
3)119 (140*.85)
4)28 (35*.8)

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3 years ago

Find the equation of the parabola that passes through

valentinak56 [21]

so we have the points of (0,-7),(7,-14),(-3,-19), let's plug those in the y = ax² + bx + c form, since we have three points, we'll plug each one once, thus a system of three variables, and then we'll solve it by substitution.

$\bf \begin{array}{cccllll} \stackrel{\textit{point (0,-7)}}{-7=a(0)^2+b(0)+c}& \stackrel{point (7,-14)}{-14=a(7)^2+b(7)+c}& \stackrel{point (-3,-19)}{-19=a(-3)^2+b(-3)+c}\\\\ -7=c&-14=49a+7b+c&-19=9a-3b+c \end{array}$

well, from the 1st equation, we know what "c" is already, so let's just plug that in the 2nd equation and solve for "b".

$\bf -14=49a+7b-7\implies -7=49a+7b\implies -7-49a=7b \\\\\\ \cfrac{-7-49a}{7}=b\implies \cfrac{-7}{7}-\cfrac{49a}{7}=b\implies -1-7a=b$

well, now let's plug that "b" into our 3rd equation and solve for "a".

$\bf -19=9a-3b-7\implies -12=9a-3b\implies -12=9a-3(-1-7a) \\\\\\ -12=9a+3+21a\implies -15=9a+21a\implies -15=30a \\\\\\ -\cfrac{15}{30}=a\implies \blacktriangleright -\cfrac{1}{2}=a \blacktriangleleft \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{and since we know that}}{-1-7a=b}\implies -1-7\left( -\cfrac{1}{2} \right)=b\implies -1+\cfrac{7}{2}=b\implies \blacktriangleright \cfrac{5}{2}=b \blacktriangleleft \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill y=-\cfrac{1}{2}x^2+\cfrac{5}{2}x-7~\hfill$

3 0

3 years ago