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Aleks04 [339]
3 years ago
15

Help W algebra!!(logs!)

Mathematics
1 answer:
tatuchka [14]3 years ago
7 0
$2,029.50 is the answer
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Simplify the radical completely.
AlladinOne [14]

Answer:

D

Step-by-step explanation:

\sqrt{300}  =  \sqrt{100 \times 3}  =  \sqrt{100}  \times  \sqrt{3}  = 10 \sqrt{3}

3 0
2 years ago
All help is much appreciated please and thank you
Klio2033 [76]
Once again similar traingles.

With same ratioes as before.

RS/RT = RV/RU=SV/TU = 1/2

\frac{w - 41}{w}  =  \frac{1}{2}  \\ 2w - 82 = w \\ w = 81 \: units
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3 years ago
Factor  56−16 56−16  using the GCF. I TRIED IT AND ITS NOT 8
Svetach [21]
It is eight. There is no way it's wrong I doubled checked.
5 0
3 years ago
Read 2 more answers
In a survey of 300 house wires. It was discovered
ruslelena [56]

Answer:

46 housewives read all three magazines.

Step-by-step explanation:

Given:

        n(A) = 150

        n(B) = 200

        n(C) = 156

        n(A∩B) = 48

        n(B∩C) = 60

        n(A∩C) = 52

         n(A∪B∪C) = 300

so we know the relation as:

  n(A∪B∪C) = n(A) + n(B) + n(C) - n(A∩B) - n(B∩C) - n(A∩C) + n(A∩B∩C)

∴ n(A∩B∩C) = n(A) + n(B) + n(C) - n(A∩B) - n(B∩C) - n(A∩C)  - n(A∪B∪C)

                    = 150 + 200+ 156 - 48 - 60 - 52 - 300

                   = 46

Hence the number of housewives that had read all three magazine is 46.

8 0
3 years ago
Using whichever equation you prefer (part a, b, or c), find the speed of light in meters per second if a mass of 3 kilograms con
pav-90 [236]
Given:\\m=3kg\\E=2.7\cdot 10^{17}J\\\\Find:\\c=?\\\\Solution:\\\\E=mc^2\\\\c^2= \frac{E}{m} \\\\c= \sqrt{\frac{E}{m}} \\\\c= \sqrt{ \frac{2.7\cdot 10^{17}J}{3} } = (2.7\cdot 10^{16} \frac{m^2}{s^2} )^{ \frac{1}{2} }=3\cdot 10^{8} \frac{m}{s}
6 0
3 years ago
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