D= -91 hope this will help you
An elliptical equation is in the form
Ax^2+Bx+Cy^2+Dy+E=0
the equation is a Hyperbola. When x and y are both squared, and exactly one of the coefficients is negative and exactly one of the coefficients is positive.
1-49x^2-98x-64y^2+256y-2831=0
2-4x^2+32x-25y^2-250y+589=0
3-81x^2+512x-64y^2-324y-3836=0
Answer:
-4
Step-by-step explanation:
7w + (-11w)
Postive negative negative
7w-11w
= - 4
so, you just use the x's from the table and plug them into the equation to find the y.
y=(1)+9
y=10
y=(2)+9
y=11
y=(3)+9
y=12
y=(4)+9
y=13
i hope this helps :)
1
is the answer you're looking for.
