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svlad2 [7]
3 years ago
11

Which term BEST describes the quadrilateral formed when line segments connect points A, B, C, and D?

Mathematics
1 answer:
NeX [460]3 years ago
3 0

Answer:

The quadrilateral formed is a trapezoid

Step-by-step explanation:

In this case, it is necessary to know what points A, B, C, and D.

If the points are equal to the following coordinate points

A (-2, 1)

B (2, 1)

C (3, -2)

D (-3, -2)

As shown in the image the answer would be a trapezoid.

________________________________

The figure cannot be a square, a rhombus or a rectangle since by definition these are:

A square has all sides of equal length and all its right angles.

A rhombus is a parallelogram that has all sides of equal length and all its angles different from right angles.

A rectangle is a parallelogram that has all its right angles.

The figure that we obtain is neither a parallelogram nor does it have all its right angles.

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Please help, fast‍♀️‍♀️
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Inequalities are used to express unequal expressions.

The inequalities from the word problems are:

  • \mathbf{m - 3.5 \le -2}.
  • \mathbf{0 \ge 2x + 1}.
  • \mathbf{-\frac 12 \ge 2k - 4}

The statements from the inequalities are:

  • -4 is not a solution to \mathbf{x + 8 < -3}
  • -6 is not a solution to \mathbf{10 \le 3 - m}
  • -1 is not a solution to \mathbf{-3x \le -12.5}

  • Graph b represents \mathbf{x > -7}

<h3>The word problems</h3>

<u>1. A number minus 3.5 is less than or equal to -2</u>

The statement can be broken down into the following expressions

\mathbf{A\ number\ minus\ 3.5 \to m - 3.5}

\mathbf{less\ than\ or\ equal\ to\ -2 \to \le -2}

So, when the expressions are brought together, we have:

\mathbf{m - 3.5 \le -2}

<u>2. Zero is greater than or equal to twice a number x plus 1</u>

The statement can be broken down into the following expressions

\mathbf{Zero\ is\ greater\ than\ or\ equal\ to \to 0 \ge }

\mathbf{twice\ a\ number\ x\ plus\ 1\  \to 2x + 1}

So, when the expressions are brought together, we have:

\mathbf{0 \ge 2x + 1}

<u />

<u>3. -1/2 is at least twice a number k minus 4</u>

The statement can be broken down into the following expressions

\mathbf{-\frac 12\ is\ at\ least \to -\frac 12 \ge }

\mathbf{twice\ a\ number\ k\ minus\ 4\  \to 2k - 4}

So, when the expressions are brought together, we have:

\mathbf{-\frac12 \ge 2k - 4}

None of the options is correct

<h3>The solutions</h3>

<u>4. Tell whether -4 is a solution to x + 8 < -3</u>

We have:

\mathbf{x + 8

Subtract 8 from both sides

\mathbf{x + 8 - 8

\mathbf{x

The above inequality means that:

<em>x is less than -11</em>

-4 is not a solution, because -4 is greater than -11

<u>5. Tell whether -6 is a solution to 10 <= 3 - m</u>

We have:

\mathbf{10 \le 3 - m}

Subtract 3 from both sides

\mathbf{10 -3\le 3 - 3 - m}

\mathbf{7 \le  - m}

Multiply both sides by -1 (the inequality sign changes)

\mathbf{-7 \ge m}

Make m the subject

\mathbf{m \le -7}

The above inequality means that:

<em>m is less than -7</em>

-6 is not a solution, because -6 is greater than -7

<u>6. Tell whether -1 is a solution to -3x <= -12.5</u>

We have:

\mathbf{-3x \le -12.5}

Divide both sides by -3 (the inequality sign changes)

\mathbf{x \ge 4\frac16}

The above inequality means that:

<em>x is greater than or equal to </em>\mathbf{4\frac16}<em />

-1 is not a solution, because -1 is less than \mathbf{4\frac16}<em />

<h3>The graph</h3>

The inequality is given as: \mathbf{x > -7}

The less than sign (>) means that:

  • The graph would use an open circle
  • The arrow must point to the right

Only graph b satisfies this condition

Hence, the graph of \mathbf{x > -7} is graph b

Read more about inequalities at:

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