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svlad2 [7]
3 years ago
11

Which term BEST describes the quadrilateral formed when line segments connect points A, B, C, and D?

Mathematics
1 answer:
NeX [460]3 years ago
3 0

Answer:

The quadrilateral formed is a trapezoid

Step-by-step explanation:

In this case, it is necessary to know what points A, B, C, and D.

If the points are equal to the following coordinate points

A (-2, 1)

B (2, 1)

C (3, -2)

D (-3, -2)

As shown in the image the answer would be a trapezoid.

________________________________

The figure cannot be a square, a rhombus or a rectangle since by definition these are:

A square has all sides of equal length and all its right angles.

A rhombus is a parallelogram that has all sides of equal length and all its angles different from right angles.

A rectangle is a parallelogram that has all its right angles.

The figure that we obtain is neither a parallelogram nor does it have all its right angles.

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TEA [102]

Answer:

To be honest i dont even know

Step-by-step explanation:

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7 0
2 years ago
Can someone help me graph this?
Elan Coil [88]

y axis is vertical x is horizontal

7 0
3 years ago
when a linear function is graphed it passes through the points (-1,1), (1,5), and (3,9) what is the rate of change for the funct
vesna_86 [32]
Use the linear slope formula to solve for m: 

m=(y2-y1)/(x2-x1)

using the points (-1,1) and (1,5) you can find the slope for the first interval:
 
m=(5-1)/(1-(-1))
m=4/2
m=2

you can double check by using the same formula on the second interval, which is (1,5) to (3,9).

m=(9-5)/(3-1)
m=4/2
m=2 

therefore, the rate of change is 2. 
5 0
3 years ago
What's the probability of pulling two red cards in a row from a deck of cards?​
monitta

Hey there! I'm happy to help!

Let's say that we don't have jokers. In that case, there are 52 cards, and half of them are red (so 26 are red). The probability of pulling a red card once is 1/2 since half the cards are red.

If we pick one out, there are only 51 total cards left and 25 red cards. So, the probability of picking one again would be 25/51.

We multiply the probabilities of these two events to find the probability of them both happening.

1/2×25/51=25/102

The probability of picking two red cards in a row is 25/102 or around 24.5%.

Have a wonderful day! :D

8 0
2 years ago
You throw a ball up and its height h can be tracked using the equation h=2x^2-12x+20.
postnew [5]

<em><u>This problem seems to be wrong because no minimum point was found and no point of landing exists</u></em>

Answer:

1) There is no maximum height

2) The ball will never land

Step-by-step explanation:

<u>Derivatives</u>

Sometimes we need to find the maximum or minimum value of a function in a given interval. The derivative is a very handy tool for this task. We only have to compute the first derivative f' and have it equal to 0. That will give us the critical points.

Then, compute the second derivative f'' and evaluate the critical points in there. The criteria establish that

If f''(a) is positive, then x=a is a minimum

If f''(a) is negative, then x=a is a maximum

1)

The function provided in the question is

h(x)=2x^2-12x+20

Let's find the first derivative

h'(x)=4x-12

solving h'=0:

4x-12=0

x=3

Computing h''

h''(x)=4

It means that no matter the value of x, the second derivative is always positive, so x=3 is a minimum. The function doesn't have a local maximum or the ball will never reach a maximum height

2)

To find when will the ball land, we set h=0

2x^2-12x+20=0

Simplifying by 2

x^2-6x+10=0

Completing squares

x^2-6x+9+10-9=0

Factoring and rearranging

(x-3)^2=-1

There is no real value of x to solve the above equation, so the ball will never land.

This problem seems to be wrong because no minimum point was found and no point of landing exists

3 0
3 years ago
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