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3 years ago

Pls answer the following. put them in order from least to greatest: 1.6, 1.6071, 1.08, 1.008.

Mathematics

1 answer:

MatroZZZ [7]3 years ago

7 0

Answer:

1.008

1.08

1.6

1.6071

Step-by-step explanation:

least to greatist

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A camera has a listed price of $876.99 before tax. If the sales tax rate is 6.75%, find the total cost of the camera with sales

avanturin [10]

Answer:

$936.18

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5 0

3 years ago

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Dimas [21]

Answer:

y = 4 and x = 12

Step-by-step explanation:

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8 0

2 years ago

Please help me figure this out

katrin2010 [14]

Step-by-step explanation:

standard form is given by Ax × By = C

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2 years ago

Read 2 more answers

Find the sumofthe geometrical progression of five terms, of which the first term is 7 and the multiplier is 7.Verify that the su

777dan777 [17]

Answer:

The sum of first five term of GP is 19607.

Step-by-step explanation:

We are given the following in the question:

A geometric progression with 7 as the first term and 7 as the common ration.

$a, ar, ar^2,...\\a = 7\\r = 7$

$7, 7^2, 7^3, 7^4...$

Sum of n terms in a geometric progression:

$S_n = \displaystyle\frac{a(r^n - 1)}{(r-1)}$

For sum of five terms, we put n= 5, a = 7, r = 7

$S_5 = \displaystyle\frac{7(7^5 - 1)}{(7-1)}\\\\S_5 = 19607$

The sum of first five term of GP is 19607.

Verification:

$2801\times 7 = 19607$

Thus, the sum is equal to product of 2801 and 7.

7 0

3 years ago

A used car dealer has 30 cars and 10 of them are lemons (i.e.~ mechanically faulty used cars), and you don't know which is which

Triss [41]

Answer: Hence, the probability that he will get at least one lemon is 0.70.

Step-by-step explanation:

Since we have given that

Number of cars = 30

Number of lemon cars = 10

Number of other than lemon cars = 30-10 = 20

According to question, he bought 3 cars,

we need to find the probability that you will get at least one lemon.

So, P(X≤1)=1-P(X=0)=1-P(no lemon)

Here, P(no lemon ) is given by

$\dfrac{20}{30}\times \dfrac{20}{30}\times \dfrac{20}{30}=(\dfrac{20}{30})^3$

so, it becomes,

$P(X\geq 1)=1-(\dfrac{20}{30})^3=1-(0.67)^3=0.70$

Hence, the probability that he will get at least one lemon is 0.70.

5 0

3 years ago