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GuDViN [60]
3 years ago
6

if $4200 is invested in a savings account for which interest is compounded semiannually, and if the $4200 turns into $4900 in 4

years, what is the interest rate of the savings account?
Mathematics
2 answers:
nydimaria [60]3 years ago
6 0
4900=4200(1+r/2)^(2*4)
Solve for r
R=(4900/4200)^(1/8))-1)*2
R=((4,900÷4,200)^(1÷8)−1)×2
R=0.039*100=3.9%
wel3 years ago
5 0

Answer:

3.89

Step-by-step explanation:

did test

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Let a triangle have sides of 137 in, 127 in,
Margarita [4]

Answer:

I think first add the side 137+ 127 +118=382 / 382cm

8 0
2 years ago
-7,-12,-17,-22,-27 find the nth term
Bess [88]

Answer:

-2 - 5n

Step-by-step explanation:

-7, -12, -17, -22, -27.....

Arithmetic Sequence

first term a = -7

difference = d = -12 - (-7) = -12 + 7 =  (-5)

nth term = a + (n-1)d

              =  -7 + (n-1)*(-5)

              = -7 + (-5)*n -1 * (-5)

             = -7 - 5n + 5

            = -2 - 5n

6 0
3 years ago
How do you find the value of √a⁴ ??<br> (ill give brainliest)
dsp73

Answer:

a^{2}

Step-by-step explanation:

√a^4 is the same as:

√a × √a × √a × √a

group them as 2 pairs of

(√a × √a) × (√a × √a)

which makes

a × a

which is the same as a^{2}

5 0
3 years ago
The equation $(x - 7)^2 + (y + 13)^2 = 12$ represents a circle. What is its radius?
miskamm [114]

Answer:

<h3>2√3</h3>

Step-by-step explanation:

The standard equation of a circle is expressed as;

(x-a)²+(y-b)² = r² where;

(a, b) is the center of the circle

r is the radius of the circle

Given the equation (x - 7)^2 + (y + 13)^2 = 12

On comparing;

r² = 12

Take the square root of both sides

√r² = √12

r = √12

r = √4*3

r = 2√3

Hence the radius of the circle is 2√3

7 0
3 years ago
I need some help with this calculus 1 question.
Cerrena [4.2K]

Answer:

(a) f'(1)=-4

(b) y+4x-4=0

Step-by-step explanation:

<u>Tangent Line of a Function</u>

Given f(x) a real differentiable function in x=a, the slope of the tangent line of the function in x=a is given by f'(x=a). Where f' is the first derivative of f.

We are given

y=x-x^5

The derivative is

y'=1-5x^4

(a) The slope of the tangent line at (1,0) is

f'(1)=1-5\cdot 1^4=-4

f'(1)=-4

(b) The equation of the tangent line can be found with the general formula of the line:

y-y_o=m(x-x_o)

Where m is the slope and the point (xo,yo) belongs to the line. We have m=-4, xo=1, yo=0, thus

y-0=-4(x-1)

Or, equivalently

y+4x-4=0

3 0
3 years ago
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