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antiseptic1488 [7]
3 years ago
7

Quickly!! Please help!! Geometry!! What is the area of the figure below?

Mathematics
1 answer:
Alex Ar [27]3 years ago
5 0

It's a parallelogram and a triangle.

The formula of an area of a It's a parallelogram:

A_P=bh

b - base, h - height

We have: b = 8 ft and h = 5ft. Substitute:

A_P=(8)(5)=40\ ft^2

The formula of an area of a tringle:

A_T=\dfrac{bh}{2}

b - base, h - height

We have: b = 10 ft and h = 5 ft. Substitute:

A_T=\dfrac{10\cdot5}{2}=\dfrac{50}{2}=25\ ft^2

The area of the figure:

A=A_P+A_T\to A=40+25=65\ ft^2

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B<br> [2 0]<br> -2 5<br> What is the determinant of B?<br> Your answer
Marianna [84]

Answer:

10

Step-by-step explanation:

Determinant = ad - bc

\det\begin{pmatrix} 2 & 0 \\-2 & 5\end{pmatrix} =\begin{vmatrix} 2 & 0 \\-2 & 5\end{vmatrix} = 2\times5 + 0\times2 = 10

8 0
3 years ago
Choose the correct equation for the parabola based on the given information. Given: Focus:(2,8) Directrix: y = 4 a. 2(y-2)= (x-
Harman [31]
<h3>Answer:  c. 8(y-6) = (x-2)^2</h3>

Explanation:

The directrix is horizontal, so the axis of symmetry is vertical. We'll have an x^2 term. The vertical distance from y = 4 to y = 8 is 4 units. Cut this in half to get 2, which is the focal distance p = 2.

The point (2,4) is directly below (2,8), and the point is on the directrix. The midpoint between (2,4) and (2,8) is (2,6). This is the vertex.

(h,k) = (2,6)

4p(y-k) = (x-h)^2

4*2(y-6) = (x-2)^2

8(y-6) = (x-2)^2

8 0
3 years ago
Hese are the values in Paul’s data set.
andrew-mc [135]
Answer: See description below.

The residuals are the differences between the predicted values and the actual values. You will need to make a scatter plot of each difference.

Here are the five points that you will need to plot:
20 - 21 = -1  (1, -1)
17 - 16 = 1 (2, 1)
9 - 10 = -1 (4, -1)
6 - 5 = 1 (5, 1)
2 - 2 = 0 (6, 0)
8 0
3 years ago
Read 2 more answers
Let B be the basis of P3 consisting of the Hermite polynomials in Exercise 21, and let p.t / D 7 ! 12t ! 8t 2 C 12t 3. Find the
Anastasy [175]

To calculate the relative vector of B we have to:

P_B=\left[\begin{array}{ccc}3\\3\\-2\\3/2\end{array}\right]

The coordenates of:

p(t)= 12t^3-8t^2-12t+7, with respect to B satisfy:

C_1(1)+C_2(2t)+C_3(-2+4t^2)+C_4(-12t+8t^3)= 7-12t-8t^2+12t^3

Equating coefficients of like powers of t produces the system of equation:

\left \{ {C_1-2C_3=7} \atop {2C_2-12C_4=-12} \right. \\\left \{ {{4C_3=-8} \atop {8C_4=12}} \right.

After solving this system, we have to:

C_1=3\\C_2= 3\\C_3= -2\\C_4= \frac{3}{2}

And the result is:

P_B=\left[\begin{array}{ccc}3\\3\\-2\\3/2\end{array}\right]

Learn more: brainly.com/question/16850761

4 0
3 years ago
Consider the limaçon with equation r = 3 4cos(θ). how does the quotient of a and b relate to the existence of an inner loop?
Delicious77 [7]

If the equation is r = 3 +4cos(θ) then because b/a>1 the curve is a limacon with an inner loop.

Given limacon with equation r=3+4cos(θ) and we have to answer how the quotient of a and b relate to the existence of an inner loop.

Equation is like a relationship between two or more variables expressed in equal to form and it is solved to find the value of variables.

formula of polar graph is similar to r= a+ b cos (θ).

Case 1. If a<b or b/a>1

then the curve is a limacon with inner loop.

Case 2. If a>b or b/a<1

Then the limacon does not have an inner loop.

Here given that r=3+4cos (θ)

It is observed that , a<b or b/a>1

Therefore the curve is limacon with an inner loop.

Hence because b/a>1 the curve is a limacon with an inner loop.

Learn more about limacon at brainly.com/question/14322218

#SPJ4

5 0
2 years ago
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