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3 years ago

Hese are the values in Paul’s data set.

2 answers:

8 0

Answer: See description below.

The residuals are the differences between the predicted values and the actual values. You will need to make a scatter plot of each difference.

Here are the five points that you will need to plot:
20 - 21 = -1 (1, -1)
17 - 16 = 1 (2, 1)
9 - 10 = -1 (4, -1)
6 - 5 = 1 (5, 1)
2 - 2 = 0 (6, 0)

Colt1911 [192]3 years ago

4 0

Answer:

20 - 21 = -1 (1, -1)

17 - 16 = 1 (2, 1)

9 - 10 = -1 (4, -1)

6 - 5 = 1 (5, 1)

2 - 2 = 0 (6, 0

Step-by-step explanation:

You might be interested in

Solve for x: 4 (1-x)+2x=-3 (x+1)

Angelina_Jolie [31]

The correct answer is: x=9
4(1-x)+2=-3(x+1 )
-4x +3x = -3 -6
-x=-9
x=9

5 0

3 years ago

A bag contains 18 balls to green five black eight blue one brown one red and one white if 17 balls of a move from the bag at ran

dimaraw [331]

Answer:

$P(Brown) = 0.0556$ or $P(Brown) = \frac{1}{18}$

Step-by-step explanation:

Given

$Total = 18$

$Green = 2$

$Black = 5$

$Blue = 8$

$Brown = 1$

$Red = 1$

$White = 1$

Required

Determine the probability of selecting a brown ball

This is calculated as thus:

$P(Brown) = \frac{Brown}{Total}$

Substitute values for Brown and Total

$P(Brown) = \frac{1}{18}$

The answer can be in fraction or solved further as;

$P(Brown) = 0.0556$

5 0

3 years ago

A psychology class consists of 14 males and 36 females. if the professor selects names from the class list using random sampling

Sonbull [250]

The probability of selecting a female student for the first picking is $\frac{36}{50} = \frac{18}{25}$
The number of students left to select from after the first two students selected is 50 - 2 = 48 students, which consist of 34 females (two have been selected) and 14 males (none has been selected so far)
The probability that the third pick is a male is $\frac{14}{48}= \frac{7}{24}$

8 0

3 years ago

Area and percent .

siniylev [52]

Answer:

a. 61.92 in²

b. 21.396 ≈ 21.4%

c. $4.71

Step-by-step explanation:

a. Amount of waste = area of rectangular piece of stock - area of two identical circles cut out

Area of rectangular piece of stock = 24 in × 12 in = 288 in²

Area of the two circles = 2(πr²)

Use 3.14 as π

radius = ½*12 = 6

Area of two circles = 2(3.14*6²) = 226.08 in²

Amount of waste = 288 - 226.08 = 61.92 in²

b. % of the original stock wasted = amount of waste ÷ original stock × 100

= 61.92/288 × 100 = 6,162/288 = 21.396 ≈ 21.4%

c. 288 in² of the piece of stock costs $12.00,

Each cut-out circle of 113.04 in² (226.08/2) will cost = (12*113.04)/288

= 1,356.48/288 = $4.71.

3 0

4 years ago

√x-3 +3=x<br> is it extraneous or not?

Ksju [112]

Answer:

extraneous

Step-by-step explanation:

extraneous

7 0

2 years ago